Three Primary Components of an Inbox:( 8 Components of an effective Email.).

Answer:

1: From Label

2: Subject Line

3: Pre- Header

4: Content

5: Call to action

6: Images'

7: Social Media Buttons

8. Unsubscribe Option

3 0

2 years ago

Linda is the education manager for a national coding service company. Once a month she holds a videoconference with all her codi

Andru [333]

Answer:

Option (D) i.e., synchronous is the correct option to the following question.

Explanation:

The following statement are the synchronous type of training because it is the type of training which is given to students or the persons for the purpose of knowledge in present time and the trainer or that person who give them information they can receive feedback and message at that time and all persons has permission to ask questions with them.

Option C is incorrect because in this type of training the interaction between the trainer and the receiver could not be established.

Option A is incorrect because the classroom-based training only for that person or the students who are available at that time at that place and in this video conferencing is not available.

8 0

2 years ago

When your purchases are swiped over the bar-code reader at the point-of-sale terminals at Wal-Mart, a _____ records the data.

nydimaria [60]

Answer: Transaction processing system

Explanation:

A transaction processing system basically records all the data in the system. It is the set of data that basically monitor all the transaction process in the system. It basically perform various transaction oriented applications in the system.

It also allow time delay in the system when the item is supposed to being sold to the actually selling of the item. There are basically various types of transaction processing system arr payroll, account payable and the inventory control.

4 0

2 years ago

3. The wildlife department has been feeding a special food to rainbow trout finger lings in a pond. A sample of the weight of 40

andrey2020 [161]

Answer:

1) 402.7 grams. This estimate is called the sample mean.

2) (399.11, 406.29)

3) The 99 percent confidence limits is between 399.11 grams and 406.29 grams.

I am 99% sure that the value lies between 399.11 grams and 406.29 grams.

Explanation:

sample size (n) = 40, the mean weight (x)= 402.7 grams and the standard deviation (σ)=8.8 grams

1) The point estimated mean weight of the population is 402.7 grams. This estimate is called the sample mean.

2) c = 99% = 0.99

α = 1 - 0.99 = 0.01

$\frac{\alpha }{2} =\frac{0.01}{2} =0.005$ .

The z score of 0.005 corresponds with the z score of 0.495 (0.5 - 0.005).

$z_\frac{\alpha }{2} =2.58$ .

The margin of error (e) = $z_\frac{\alpha }{2}*\frac{\sigma}{\sqrt{n} } =2.58*\frac{8.8}{\sqrt{40} } =3.59$

The confidence interval = x ± e = 402.7 ± 3.59 = (399.11, 406.29)

3) The 99 percent confidence limits is between 399.11 grams and 406.29 grams.

I am 99% sure that the value lies between 399.11 grams and 406.29 grams.

8 0

2 years ago

Five technology tools and their uses​

Five technology tools and their uses