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storchak [24]
2 years ago
8

Solve: let f(x)=2x-1 and g(x)=x^2-4. find g(f(x))

Mathematics
1 answer:
Stella [2.4K]2 years ago
3 0
<h3>Answer:   g(f(x)) = 4x^2 - 4x - 3</h3>

Work Shown:

g(x) = x^2 - 4

g(f(x)) = ( f(x) )^2 - 4

g(f(x)) = ( 2x-1 )^2 - 4

g(f(x)) = (2x-1)(2x-1) - 4

g(f(x)) = 4x^2-2x-2x+1 - 4

g(f(x)) = 4x^2 - 4x - 3

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Make a table for each function rule. Then graph each equation using the points you created.
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Answer:

1.f(x)=2x-5

i will take the set {-2,-1,0,1,2}

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2.f(x)=-3x+6

i will the take the set {-2,-1,0,1,2} too

f(-2)=-3(-2)+6=6+6=12

f(-1)=-3(-1)+6=3+6=9

f(0)=-3(0)+6=6

f(1)=-3(1)+6=-3+6=3

f(2)=-3(2)+6=-6+6=0

{12,9,6,3,0}

3.f(x)=2/3.x+4

{-2,-1,0,1,2}

f(-2)=2/3(-2)+4=-4/3+4=(-4+12)/3=8/3

f(-1)=2/3(-1)+4=-2/3+4=(-2+12)/3=10/3

f(0)=2/3(0)+4=4

f(1)=2/3(1)+4=2/3+4=(2+12)/3=14/3

f(2)=2/3(2)+4=4/3+4=(4+12)/3=16/3

{8/3,10/3,4,14/3,16/3}

you're can graph those coordinates

actually you can take other coordinates...

CMIIW

,

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Answer:

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Step-by-step explanation:

Hope it helps!

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Step-by-step explanation:

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