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3 years ago

Nathan nets $680 every other week. How much does

1 answer:

5 0

B. Average $2946.67; Safe $1360

This is because if you multiply $680 x 4( a month) = $2720 which is close to $2946
You now divide 2720/2 yup get $1360

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How the hell did I get a notification that I answered a question i didn't create???

igomit [66]

Answer:

i dont know same thing

Step-by-step explanation:

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2 years ago

Read 2 more answers

Use the fundamental identities and appropriate algebraic operations to simplify the following expression. (18 +tan x) (18-tan x)

andrezito [222]

Answer:

a) $\left(18+\tan \left(x\right)\right)\left(18-\tan \left(x\right)\right)+\sec ^2\left(x\right)=325$

b) The lowest point of $y=\cos \left(x\right)$ , $0\leq x\leq 2\pi$ is when x = $\pi$

Step-by-step explanation:

a) To simplify the expression $\left(18+\tan \left(x\right)\right)\left(18-\tan \left(x\right)\right)+\sec ^2\left(x\right)$ you must:

Apply Difference of Two Squares Formula: $\left(a+b\right)\left(a-b\right)=a^2-b^2$

$a=18,\:b=\tan \left(x\right)$

$\left(18+\tan \left(x\right)\right)\left(18-\tan \left(x\right)\right)=18^2-\tan ^2\left(x\right)=324-\tan ^2\left(x\right)$

$324-\tan ^2\left(x\right)+\sec ^2\left(x\right)$

Apply the Pythagorean Identity $1+\tan ^2\left(x\right)=\sec ^2\left(x\right)$

From the Pythagorean Identity, we know that $1=-\tan ^2\left(x\right)+\sec ^2\left(x\right)$

Therefore,

$324[-\tan ^2\left(x\right)+\sec ^2\left(x\right))]\\324[+1]\\325$

b) According with the below graph, the lowest point of $y=\cos \left(x\right)$ , $0\leq x\leq 2\pi$ is when x = $\pi$

3 0

3 years ago

Allison has 5 times as many baseball cards as football cards. In all she has 120 baseball and football cards. How many baseball

bekas [8.4K]

Allison has 600 baseball cards

3 0

3 years ago

PLEASE SOMEONE HELP ME QUICKLY!!!!!!

Nastasia [14]

Hi, TRUEBOSS72!

The answer to your question I believe is $t(x) = 309.125^{x}$

-ASIAX ∵<span>Frequent Answerer</span>∴

P.S. If I am wrong about it please let me know.

3 0

3 years ago

Suppose that 35 people are divided in a random manner into two teams in such a way that one team contains 10 people and the othe

Effectus [21]

Answer:

0.5798 or 57.98%

Step-by-step explanation:

The total number of ways to form the two teams is the combination of choosing 10 people out of 35 (₃₅C₁₀). The number of possibilities that A and B are both on the 10-people team is given by the combination of choosing 8 people (since two are fixed) out of 33 (₃₃C₈).The number of possibilities that A and B are both on the 25-people team is given by the combination of choosing 10 people out of 33 (₃₃C₈).

Therefore, the probability that two particular people A and B will be on the same team is:

$P = \frac{_{33}C_8+_{33}C_{10}}{_{35}C_{10}} \\\\P=\frac{\frac{33!}{(33-8)!8!}+\frac{33!}{(33-10)!10!} }{\frac{35!}{(35-10)!10!}} \\\\P=\frac{69}{119} = 0.5798$

The probability is 0.5798 or 57.98%.

8 0

3 years ago