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3 years ago

The perimeter of the rectangle above is:

Mathematics

1 answer:

Nonamiya [84]3 years ago

4 0

Step-by-step explanation:

given,

length = 4x²

breadth/width = y²

we know,

perimeter = 2l + 2b

so,

2(4x²) + 2(y²)

→ 8x² + 2y²

option A is correct

hope this answer helps you dear...take care and may u have a great day ahead!

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Karen is starting a career as a professional wildlife photographer and plans to photograph Canadian Geese at one of the staging

balandron [24]

Answer:

$5000*0.816 = $4082

Step-by-step explanation:

It's a strange question, but based on the statement and the question it sounds like it's a poisson distribution:

* For 3 days she was able to get 2 good shots (typical of that time of the year)

* Good shots happen randomly

* Each day is independent of another

Let's call 'p' the probability that she makes a good shot per day

Let's call 'n' the number of days Karen is taking shots.

So, if in 3 days he got 2 good shots and that is typical at that time of the year, then the expected value for the number of good shots (X) is:

$E(x)=\frac{2}{3}$

For a Poisson distribution $E (x)=\lambda\\\lambda= np$

So:

$\lambda =\frac{2}{3}$

For a Poisson distribution the standard deviation is:

$\sigma = \sqrt{\lambda}\\\sigma = \sqrt{\frac{2}{3}}$

$\sigma = 0.816$ this is the standard deviation for the number of buentas taken.

So the standard deviation for income is the price of each shot per sigma

$5000*0.816 = $4082, which is the desired response.

3 0

3 years ago

Write an equivalent expression. 2 + 4(c + 7)

Alex777 [14]

2 + 4 (c + 7)
2 + 4c + 28
combine liked terms
4c + 30

Answer:
B) 30 + 4c

3 0

2 years ago

Ranch High School hosted a basketball tournament to raise money to update the school's gym. The cost for all the necessary suppl

Goryan [66]

Answer:

No.

Step-by-step explanation: Sadly the school will not have enough money to update the school. The amount of money they made was,$ 2,367.5 dollars. They would need $2367.5 more to update the school.

4 0

3 years ago

Suppose that the value of a stock varies each day from $13 to $24 with a uniform distribution. (a) Find the probability that the

bogdanovich [222]

Answer:

a. P= 0.6364

b. P = 0.3636

c. Q = $21.25

d. P = 0.5

Step-by-step explanation:

given data

value of a stock varies = $13 to $24

solution

P (stock value is more than $17)

P = $\frac{(24-17)}{(24-13)}$

P = $\frac{7}{11}$

P = 0.6364

and

P (value of the stock is between $17 and $21)

P = $\frac{(21-17)}{(24-13)}$

P = $\frac{4}{11}$

P = 0.3636

and

Let the upper quartile be Q

$\frac{(24 - Q)}{(24 - 13)} = 0.25$

$\frac{(24 - Q)}{11} = 0.25$

(24 - Q) = 2.75

Q = $21.25

and

P(X > 20 | X > 16)

P = $\frac{(24-20)}{(24-16)}$

P = $\frac{4}{8}$

P = 0.5

3 0

3 years ago

Please help me its math 10 points

prisoha [69]

Answer:

it should be 319

Step-by-step explanation:

7 0

1 year ago

Read 2 more answers