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algol13
2 years ago
6

1. Factorise completelty. a) x²-x-132​

Mathematics
1 answer:
Natasha_Volkova [10]2 years ago
5 0

Answer:

(x - 12)(x +11)

Step-by-step explanation:

Hello!

We can factor by grouping. Find two numbers that multiply to -132 and add to -1.

  • The two numbers are 11 and -12.
  • Expand -x to 12x + 11x
  • <u>Factor by grouping</u>
<h3 /><h3>Factor by Grouping</h3>
  • x^2 - x - 132
  • x^2 + 11x - 12x - 132
  • x(x + 11) - 12(x + 11)
  • (x - 12)(x +11)

The factored form is (x - 12)(x +11).

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Factor the following expression 2x^2 - 11x+12
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Which number line shows the solution set for |m| = 4
Margaret [11]

Answer:

Last choice that shows points on +4 and -4 is the correct graph.

Step-by-step explanation:

We have been given equation |m|=4. Now we need to find out which of the given number lines shows the corret solution set for |m|=4.

We know that |x|=a can be broken into two parts as:

x=+a and x=-a

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m=+4 and m=-4

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4 0
3 years ago
find the surface area of a right regular hexagonal pyramid with sides 3 cm and slant heights 6cm. show all of your work.​
DedPeter [7]

Answer:

The surface area of right regular hexagonal pyramid = 82.222 cm³

Step-by-step explanation:

Given as , for regular hexagonal pyramid :

The of base side = 3 cm

The slant heights = 6 cm

Now ,

The surface area of right regular hexagonal pyramid = \frac{3\sqrt{3}}{2}\times a^{2} + 3 a \sqrt{h^{2}+ 3\times \frac{a^{2}}{4}}

Where a is the base side

And h is the slant height

So, The surface area of right regular hexagonal pyramid = \frac{3\sqrt{3}}{2}\times 3^{2} + 3 \times 3 \sqrt{6^{2}+ 3\times \frac{3^{2}}{4}}

Or, The surface area of right regular hexagonal pyramid = \frac{3\sqrt{3}}{2}\times 9 + 9 \sqrt{36+ 3\times \frac{9}{4}}

Or,  The surface area of right regular hexagonal pyramid = 23.38 + 9 × \frac{171}{4}

∴  The surface area of right regular hexagonal pyramid = 23.38 + 9 × 6.538

I.e The surface area of right regular hexagonal pyramid = 23.38 + 58.842

So,  The surface area of right regular hexagonal pyramid = 82.222 cm³ Answer

6 0
4 years ago
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