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nydimaria [60]
4 years ago
9

I know someone smart is out there that could answer this question. it is 9th grade Algebra if you dont know that dont click.

Mathematics
1 answer:
faust18 [17]4 years ago
4 0

Answer:

1. d-even lc- -

2. d- odd lc- +

3. type- odd lc- +

4. type- even lc- -

5. d- even lc- - type even

6 d- odd lc- + type- even

Step-by-step explanation:

when the degree is odd, one leg goes down one goes up

when the degree is even, both legs go up or down

when the leading coefficient is negative the end behavior is -∞

when the leading coefficient is positive, the end behavior ∞

a function is odd when both legs go down

a function is even when the legs go in different directions

a function is neither when it isn't a function (think vertical line test)

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REALLY NEED MATH MIDPOINT STUFF HELP
elena-14-01-66 [18.8K]
The answer to this question would be: (6.5 , 8.5)

To answer this question, you need to determine the x and y distance of both point. From A point the distance would be: 
X distance= 14-4= 10
Y distance= 10-8= 2

Making it into 1:3 ratio means that dividing the line into 4 parts then take 1 part from the point A, or 3 part from point B. From A point the distance would be 1/4 total distance
The location would be:
X= 4 + (10*1/4)= 6.5
Y= 8+ (2*1/4)= 8.5
(6.5 , 8.5)
4 0
3 years ago
Read 2 more answers
What is the value of x?
liraira [26]
It would be 12 because it is just the size of a ruler if you use a online ruler

7 0
4 years ago
14 rounded to the nearest tenth
mr_godi [17]
The answer would be 10 because anything under 4 rounds down (including 4 itself, unlike 5, which rounds up. 
5 0
4 years ago
Can you guys help me out on this? I'm still learning sign, cosign, and tangent :)
Yakvenalex [24]

Answer:

\sin d = \frac{4}{7} ; \sin e = \frac{\sqrt{33} }{7}

\cos d = \frac{\sqrt{33} }{7} ; \cos e = \frac{4}{7}

\tan d = \frac{4}{\sqrt{33} } ; \tan e = \frac{\sqrt{33} }{4}

Step-by-step explanation:

For a right angled triangle with one of its angle α (alpha) :-

  • \sin \alpha = \frac{Side \: opposite \: to \: \alpha }{Hypotenuse \: of \: the \: triangle}
  • \cos \alpha  = \frac{Side \: adjacent \: to \: \alpha }{Hypotenuse \: of \: the \: triangle}
  • \tan \alpha  = \frac{Side \: opposite \: to \: \alpha }{Side \: adjacent \: to \: \alpha }

__________________________________________________

According to the question ,

1) When α (alpha) = d

  • \sin d = \frac{4}{7}
  • \cos d = \frac{\sqrt{33} }{7}
  • \tan d = \frac{4}{\sqrt{33} }

2) When α (alpha) = e

  • \sin e = \frac{\sqrt{33} }{7}
  • \cos e = \frac{4}{7}
  • \tan e = \frac{\sqrt{33} }{4}

3 0
3 years ago
Combine like terms and classify the polynomial by the number of terms. 9xy – 3y + 6xy – 3y A. trinomial B. monomial C. binomial
Leni [432]
To combine like terms, check if there are any terms just like the first one, and we see 6xy. 9xy + 6xy = 15xy. So that is one term. Now I would see if the second term has any terms like the first one, and we see -3y. So -3y + (-3y), we would get -6y. That means our polynomial is now 15xy - 6y, and because this has two terms, it is a binomial. Hope this helps. Please rate, leave a thanks, and mark a brainliest answer. (Not necessarily mine). Thanks, it really helps!
8 0
3 years ago
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