3+10i=4i-18
3+6i=-18
6i=-21
-7/2
-3 1/2
The question is incomplete. The complete question is :
Nate starts a lawn-mowing business. In his business, he has expenses and revenue. Nate's expenses are the cost of the lawn mower and gas, and his revenue is $25 per lawn. At what point will Nate's revenue exceed his expense?
Cost of lawn mower = $ 200
Cost of gasoline = $ 2 per lawn
Solution :
Given :
Cost of the lawn mower = $ 200
The cost of gasoline expense for one lawn = $ 2
The revenue generated for one lawn = $ 25
So let the number of lawn to be mowed = x
Therefore the total expenses = 
So, the total revenue = 
The point for which the revenue will exceed the total expenditure will be :

So at 
Thus the revenue exceeds the total expenditure after mowing 9 number of lawns.
No clue but I gunna guess and say 2
<span>f(x)=5(x+4)^3/2, let y = f(x).
</span>
<span>y =5(x+4)^3/2. The y intercept is value of y when x = 0
y intercept = </span><span>5(0+4)^3/2 = 5* 4^3.2 = 5*6 = 30. Use your calculator.
y intercept = 30
</span>
Answer:
8 hours
Step-by-step explanation:
1. Subtract value of tips she got that day
87.05 - 50.25 = 36.8
36.8 is the actual payment for her job that day
2. Divide 36.8 with paid/hour (4.6)
36.8 ÷ 4.6 = 8 hours