If a^b = c, then log(base a)(c) = b. It becomes a question - to what power bust we raise a to get c?
In this case a = 8, b = (1/3), c = 2. Therefore:
log(base 8)(2) = (1/3)
I hope this helps :)
Let f(x) = y.
y = 4x - 12
Let x = 0
y = 4(0) - 12
y = - 12
This leads to the point (0, -12).
Let y = 0.
0 = 4x - 12
1 2 = 4x
12/4 = x
3 = x
This leads to the point (3, 0).
We now graph both points and then connect each point with a straight line.
Answer:
48 orders
Step-by-step explanation:
so 10 dozen is 120 because 12(10) is 120. we first subtract 120-28, which is 96. divided 96 by 2 to get 48.
equation: (12(10)-28)/2=x
Answer:
I don't understand
Step-by-step explanation:
