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Anettt [7]
1 year ago
11

Been trying at this can't please help lol

Mathematics
1 answer:
xz_007 [3.2K]1 year ago
4 0

To add or sum this arrary, beg ∈ {array} {r} 37 \202\ + 160/ ∈  end {array} gives <u>A) 399</u>.

<h3>What is an array?</h3>

An array is a data structure made up of some elements.

The sum of all elements in an array is found by adding up the elements in the array.

<h3>Data and Calculations:</h3>

Elements of the array = 37, 202, and 160

The sum of the array, 37 + 202 + 160 = 399

Thus, to add or sum this arrary, beg ∈ {array} {r} 37 \202\ + 160/ ∈  end {array} gives <u>A) 399</u>.

Learn more about arrays at brainly.com/question/23698059

#SPJ1

<h3>Question:</h3>

Add beg ∈ {array} {r} 37 \202\ + 160/ ∈  end {array}

<h3>Answer Options:</h3>

A) 399

B) 389

C) 400

D) 409

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You can find out in two different ways, either use scientific notation or a calculator. If you go 3 steps to the right (since it's a positive power) you will get 6040. Hope this helped. :)

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2 years ago
The lcm of 2 numbers is 60 and one of the numbers is 7 less than the other number
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3 years ago
What radius of a circle is required to inscribe a regular hexagon with an area of 210.44 cm2 and an apothem of 7.794 cm
alekssr [168]
We know that

[area of a regular hexagon]=6*[area of one <span>equilateral triangle]
</span>210.44=6*[area of one equilateral triangle]
[area of one equilateral triangle]=210.44/6-----> 35.07 cm²

[area of one equilateral triangle]=b*h/2
h=7.794 cm
b=2*area/h------> b=2*35.07/7.794------>b= 9 cm

the length side of a regular hexagon is 9 cm
<span>applying the Pythagorean theorem
</span>r²=h²+(b/2)²------>r²=7.794²+(4.5)²------> r²=81--------> r=9 cm

<span>this last step was not necessary because the radius is equal to the hexagon side------> (remember the equilateral triangles)
</span>
the answer is
the radius is 9 cm
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3 years ago
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