Answer:
6.68, 13.37, 14.95
Step-by-step explanation:
One of the legs is twice as long as the other.
b = 2a
The perimeter is 35.
35 = a + b + c
The triangle is a right triangle.
c² = a² + b²
Three equations, three variables. Start by plugging the first equation into the second and solving for c.
35 = a + 2a + c
c = 35 − 3a
Now plug this and the first equation into the Pythagorean theorem:
(35 − 3a)² = a² + (2a)²
1225 − 210a + 9a² = a² + 4a²
1225 − 210a + 4a² = 0
Solve with quadratic formula:
a = [ -(-210) ± √((-210)² − 4(4)(1225)) ] / 2(4)
a = (210 ± √24500) / 8
a ≈ 6.68 or 45.82
Since the perimeter is 35, a = 6.68. Therefore, the other sides are:
b ≈ 13.37
c ≈ 14.95
2x^2 + 8x - 12 = 0..divide by 2
x^2 + 4x - 6 = 0
x^2 + 4x = 6...add 4 to both sides of the equation
x^2 + 4x + 4 = 6 + 4
(x + 2)^2 = 10....<== ur constant is 10
x + 2 = (+-)sqrt 10
x = -2 (+ - ) sqrt 10
x = -2 + sqrt 10
x = -2 - sqrt 10
Answer:
Perpendicular H = 5.244 m (Approx)
Step-by-step explanation:
Given:
Hypotenuse = 9.4 m
Base = 7.8 m
Find:
Perpendicular H
Computation:
Perpendicular H = √Hypotenuse² - Base²
Perpendicular H = √9.4² - 7.8²
Perpendicular H = √Hypotenuse² - Base²
Perpendicular H = 5.244 m (Approx)
The set of natural numbers greater than or equal to 6 will be 6, 7, 8, 9, 10, ....
<h3>How to illustrate the information?</h3>
It should be noted that the first information is about the set of natural numbers greater than or equal to 6. Therefore, they will be 6 and above.
It should be noted that the descriptive form simply states in words the elements that are in a set. It is the verbal description of the elements in the set. It is the determination of the elements that belong to a set and those that doesn't.
Also, the way that a set is described is known as the roster form. In this case, the contents of a set can be described by listing the elements that are in the set which are separated by a comma inside the bracket.
Also, the roster form: (5, 7, 9, 11) indicates odd natural numbers. The numbers that are given are odd.
Learn more about numbers on:
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