9^2pi is 81pi for the total region. 6^2 is 36pi for the unshaded region. Subtract those 2 values to find the area of just the shaded region
Answer:
3x+6
Step-by-step explanation:
(x+2)3
3(x)+3(2)
3x+6
Answer:
intensity =
intensity =
depth = 333.33 m
Step-by-step explanation:
given data
deep = 10 m
intensity = Io
intensity = Io/3
to find out
intensity of light at 50 m and 100 m and 1/100 of initial intensity remain ?
solution
we know here that intensity is inversely proportional to deep so
intensity = k ×
.................1
here k is constant
so we have given 10 m deep so
= 
so k = Io ×
................2
so from equation 1 when 100 m deep and 50 m deep
intensity = k ×
intensity = Io ×
×
intensity =
and
intensity = Io ×
×
intensity =
and
at intensity Io/100
intensity = k ×
= Io ×
×
D = 333.33 m
so depth = 333.33 m
Using formula sin^2 x +cos^2 x = 1 you get 1 - cos^2(9x) = sin^2(9x)
so in this way this fraction will be rewrited
sin9x/(1-cos^2(9x) = sin9x / sin^2(9x) = 1/sin9x
Change it
you need to change it because you cant plot down that equation