The equation of the line in slope intercept form is y = 2x - 2.
<h3>How to find the equation of a line?</h3>
The equation of a line can be represented in different form such as slope intercept form, point slope form, standard form and general form.
The equation of a line can be represented in slope intercept form as follows:
y = mx + b
where
Therefore, the slope of the line can be found as follows:
using (0, - 2)(2, 2)
m = 2 + 2 / 2 - 0
m = 4 / 2
m = 2
Therefore, the y-intercept can be solved as follows:
using (0, -2)
y = 2x + b
-2 = 2(0) + b
b = -2
Therefore, the equation is y = 2x - 2
learn more on equation of a line here: brainly.com/question/14200719
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( 7, 10.5 )
<em>Solution:
</em><em />
y = 2x - 3.5
x - 2 y = -14
Plug the first equation into the second equation like so;
x - 2 ( 2x - 3.5 ) = -14
Distribute -2 to 2x and -3.5
Your equation should now look like this:
x - 4x + 7 = -14
You want common numbers to be in the same side so you subtract 7 from both sides
x - 4x + 7 - 7 = -7 - 14
Now simplify both sides
x - 4x = -3x
- 7 - 14 = -21
In order to solve for x you need to get x by itself, so you divide both sides by -3
-3x / -3 = x
-21 / -3 = 7
x = 7
In order to solve for y you need to plug x in
(You can plug it into either equation, but I'm plugging it into the first one)
y = 2 (7) - 3.5
y = 14 - 3.5
y = 10.5
Hello!
Let’s do it step-by-step, shall we? Don’t worry! These problems can be a bit tricky but you’ll get it in no time! It’s really simple.
So, we have (-7)(-5)
This means that the problem will be multiplied because of the parentheses. They substitute the multiplication sign.
So, we have -7 (multiplied by) -5= 35
So your answer would be 35. Hope this helps :) and good luck!
A ) This is a quadratic function:
y = a x² + b x + c
If the starting point is ( 0, 0 ) then c = 0
b ) The function is:
y = - 0.2 x² + 3.6 x
( with coefficients to the nearest tenth )
The graph is in the attachment.
c ) The roots:
x 1 = 0,
0.2 x = 3.6
x = 3.6 : 0.2
x 2 = 18d ) This is near the target ( 17 m ) . So the pumpkin
will hit near the target.