Answer:
I think its scientific theory is the same as a true statement.
The answer would be C) reproduce or the third option.
Answer:
probability of the child having attached earlobes since it is recessive i.e (yy)
=1/4
=0.25 × 100%
=25%
Explanation:
If two heterozygous individuals have a child
i.e let the heterozygous individuals be = Xy
if both traits crosses together; their F₁ offspring will be; (XX, Xy, Xy, yy)
Xy × Xy
X y
X XX Xy
y Xy yy
probability of the child having attached earlobes since it is recessive i.e (yy)
=1/4
=0.25 × 100%
=25%
Answer:
a dominant mutation
Explanation:
A monohybrid testcross is a cross-breeding experiment used to determine if an individual exhibiting a dominant phenotype is homo-zygous dominant or heterozygous for a particular phenotypic trait (in this case, wing length). In a monohybrid testcross, a 1:1 phenotypic ratio shows that the dominant parental phenotype was a heterozygote for a single gene that has complete dominance. Moreover, a 3:1 ratio in the F2 is expected of a cross between heterozygous F1 individuals, which means that 75% of individuals with short wings have the dominant allele that masks the expression of the long-wing trait (i.e. the recessive allele).
<em>During dna replication, the enzyme dna polymerase adds new nucleotides to the </em><em>3</em><em>'</em><em> end of the sugar in the growing strand</em>
