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1 year ago

Can someone help me please

Mathematics

2 answers:

8_murik_8 [283]1 year ago

8 0

Answer:

$2x^2+4x+2$

Step-by-step explanation:

$(f \circ g)(x)=f(g(x)) \\ \\ =f(x+1) \\ \\ =2(x+1)^2 \\ \\ =2(x^2+2x+1) \\ \\ =2x^2+4x+2$

schepotkina [342]1 year ago

5 0

Answer:

the other answer is right mark them as brainliest!!!

Step-by-step explanation:

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Find the value of f(3) if f(x) = 4x^2 - 8x 3. a. 3 b. 12 c. 15 d. 18

Vladimir [108]

I hope this helps you

x=3

f (3)=4.3^2-8.3+3

f (3)=36-24+3=15

f (3)=4.3^2-8.3-3=36-24-3=5

3 0

3 years ago

Va rog e urgent am nevoie de raspuns

Lady_Fox [76]

Answer: 4

Explanation:

f(x) = 2x - 1

f(√2) = 2√2 - 1

f(1) = 2(1) - 1

= 2 - 1

= 1

f(√3) = 2√3 - 1

*******************************************************

$\frac{f(\sqrt{2})-f(1)}{\sqrt{2}-1} +\frac{f(\sqrt{3})-f(\sqrt{2})}{\sqrt{3}-\sqrt{2}}$

= $\frac{(2\sqrt{2}-1)-1}{\sqrt{2}-1} +\frac{(2\sqrt{3}-1)-(2\sqrt{2}-1)}{\sqrt{3}-\sqrt{2}}$

= $\frac{2\sqrt{2}-2}{\sqrt{2}-1} +\frac{2\sqrt{3}-2\sqrt{2}}{\sqrt{3}-\sqrt{2}}$

= $\frac{2\sqrt{2}-2}{\sqrt{2}-1}(\frac{\sqrt{2}+1}{\sqrt{2}+1})+\frac{2\sqrt{3}-2\sqrt{2}}{\sqrt{3}-\sqrt{2}}(\frac{\sqrt{3}+\sqrt{2}}{\sqrt{3}+\sqrt{2}})$

= $\frac{4+2\sqrt{2}-2\sqrt{2}-2}{2 - 1} + \frac{6 +2\sqrt{6}-2\sqrt{6}-4}{3-2}$

= $\frac{2}{1} +\frac{2}{1}$

= 4

3 0

3 years ago

Consider that a 1/2 cup serving of 1% cottage cheese is equivalent to 125 grams. If 1 ounce of cottage cheese is equivalent to 2

VikaD [51]

Answer:

4.42 ounces.

Step-by-step explanation:

We have been given that a 1/2 cup serving of 1% cottage cheese is equivalent to 125 grams. 1 ounce of cottage cheese is equivalent to 28.35 grams. We are asked to find the ounces in 1/2 cup serving.

We will use proportions to solve our given problem.

$\frac{\text{Ounce}}{\text{Grams}}=\frac{1}{28.25}$