6 is the cube root of 216.
I hope this helps! :D
Answer:
Option C is false.
Step-by-step explanation:
A. We are given; 0.7 < 4/5
Now, 4/5 in decimal form is written as 0.8.
Thus,0.7 is less than 0.8. So statement is true.
B) We are given: 2/3 > 0.34
Now, 2/3 in decimal form is written as 0.67.
Thus,0.67 is greater than 0.34, so statement is true.
C) We are given: 2.26 > 214
214 is obviously greater than 2.26. Thus statement is false.
D) We are given: 35/6 > 37/8
Now, 35/6 in decimal form is written as 5.83.
Likewise, 37/8 is written in decimal form as 4.63
Thus,5.83 is greater than 4.63, so statement is true.
Finally, the only false one is Option C
Answer:
Step-by-step explanation:
Domain of a function represents the set of x-values (input values) and y-values (output values) of the function represent the Range of the function.
Given function is,
If Domain (input values) of this function is,
{-12, -6, 3, 15}
Table for the input-output values of this function,
x -6 3 15 -12
y 11 5 -3 15
Answer:
the answer is 48/100 im pretty sure .
Step-by-step explanation:
Answer:
4.4
Step-by-step explanation:
The parent function of this graph is: y = sin(x)
The sine function is periodic, meaning it repeats forever.
Standard form of a sine function:

where:
- A = amplitude (height from the mid-line to the peak)
- 2π/B = period (horizontal distance between consecutive peaks)
- C = phase shift (horizontal shift - positive is to the left)
- D = vertical shift
The <u>period</u> is the horizontal distance between consecutive peaks, which is the same as <u>twice the horizontal distance between the intersection of the curve and the mid-line</u>.
Given consecutive points of intersection between the curve and the mid-line:
Therefore, the horizontal distance between these two points is:
5.9 - 3.7 = 2.2
⇒ Period = 2.2 × 2 = 4.4
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To create the equation for the function.
From inspection of the given graph:
- Amplitude (A) = 6
- Mid-line is y = 5
- Vertical shift (D) = +5
Period = 2π/B = 4.4 ⇒ B = 5π/11
Phase Shift (C) = -3.7
Substituting the values into the standard form:

