3. Two identical balloons are filled, one with helium and one with nitrogen at the same temperature. If the nitrogen balloon lea
ks at the rate of 75 mL per hour, what will be the rate of leakage from the helium balloon
1 answer:
Answer:
140.32mL per hour
Step-by-step explanation:
Rate of leakage of nitrogen ballon = 75 mL/h
Rate of leakage of helium ballon = x
Molar mass of nitrogen= Mn = 14
Molar mass of helium = Mh = 4
Effusion formula
Rate of effusion of helium/ Rate of effusion of nitrogen= √(Molar mass of nitrogen/Molar mass of helium)
Rate of effusion of helium = 75mL/h * √(14/4)
= 140.32mL/h
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