Given:
The graph of a function 
.
To find:
The interval where 
.
Solution:
From the given graph graph it is clear that, the function before x=0 and after x=3.6 lies above the x-axis. So, for 
and 
.
The function between x=0 and x=3.6 lies below the x-axis. So, 
for 
.
Now,
For 
, the graph of h(x) is above the x-axis. So, .
For 
, the graph of h(x) is below the x-axis. So, .
For 
, the graph of h(x) is below the x-axis. So, .
Only for the interval , we get .
Therefore, the correct option is A.
2x^2 + 8x - 12 = 0..divide by 2
x^2 + 4x - 6 = 0
x^2 + 4x = 6...add 4 to both sides of the equation
x^2 + 4x + 4 = 6 + 4
(x + 2)^2 = 10....<== ur constant is 10
x + 2 = (+-)sqrt 10
x = -2 (+ - ) sqrt 10
x = -2 + sqrt 10
x = -2 - sqrt 10
2730/10,000 in decimal notation is 0.273
Okay. An obtuse triangle is any triangle that has 1 angle that measures more than 90°. As we can see, angle QRS measures 76° and angle PRQ measures 104°. 104 > 90. Triangle PQR is a closed figure, and a triangle measures 180° total. There can only be 1 obtuse angle in any triangle. PRQ is an obtuse angle. Therefore, triangle PQR is an obtuse triangle.
