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1 year ago

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Rick is going to buy donuts for his family. Each donut costs $1.25. If the number of donuts Rick buys is represented using the l

etter r, which expression represents the total cost?

1 answer:

Strike441 [17]1 year ago

3 0

The algebraic expression that represents the total cost would be: A. 1.25r.

<h3>How to Write an Algebraic Expression?</h3>

Given that the number of donuts Rick buys for his family is represented by letter "r", and we also know that:

cost of each donut = $1.25.

Using an algebraic expression, we can create a mathematical expression that shows the total cost for Rick to by a given number of donuts for his family.

Thus:

1 donut = 1.25

r donuts would cost: 1.25 × r = 1.25r.

Therefore, the algebraic expression that represents the total cost would be: A. 1.25r.

Learn more about algebraic expression on:

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Which number can each term of the equation be multiplied by to eliminate the fractions before solving? 6 –3/4x +1/3 =1/2 x + 5

irga5000 [103]

Answer:

The number is 12.

Step-by-step explanation:

Given: $6-\dfrac{3}{4}x+\dfrac{1}{3}=\dfrac{1}{2}x+5$

We need to find a number multiply to each term to get rid of fraction.

We will find LCD of denominator.

First we see the numbers at denominator

Denominators are 4,3,2

Now, we will find the LCD of 2,3, and 4

Factor of 2: 2x1

Factor of 3: 3x1

Factor of 4: 2x2x1

LCD = 2x2x3 = 12

If we multiply by 12 to each term to eliminate the fraction.

Simplest equation:

$12\cdot 6-12\cdot \dfrac{3}{4}x+12\cdot \dfrac{1}{3}=12\cdot \dfrac{1}{2}x+12\cdot 5$

$72-9x+4=6x+60$

Hence, The number is 12.

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3 years ago

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In ABC the measure of angle A is 2x+4 , the measure of angle B is 4x+2 , and the measure of angle C is 2x-1. What are the measur

Lynna [10]

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(3, 5)

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Point (3, -5) is 5 units below the x-axis.

After it is reflected, it will be 5 units above the x-axis.

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What are the solutions to the following system?

bija089 [108]

The solutions are $(\sqrt{2},-1) \text { and }(-\sqrt{2},-1)$ .

Solution:

Given equation:

$-2 x^{2}+y=-5$

Add $2 x^{2}$ on both sides.

$-2 x^{2}+y+2 x^{2}=-5+2 x^{2}$

$y=-5+2 x^{2}$ -------- (1)

$y=-3 x^{2}+5$ (given) -------- (2)

Equate (1) and (2).

$-5+2 x^{2}=-3 x^{2}+5$

Add $3 x^{2}$ on both sides.

$-5+2 x^{2}+3 x^{2}=-3 x^{2}+5 +3 x^{2}$

$-5+5x^{2}=5$

Add 5 on both sides.

$-5+5x^{2}+5=5+5$

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Divide by 5 on both sides, we get

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Taking square root on both sides, we get

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Substitute $x=\sqrt{2}$ in (1).

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Substitute $x=-\sqrt{2}$ in (1).

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Therefore the solutions are $(\sqrt{2},-1) \text { and }(-\sqrt{2},-1)$ .

Option C is the correct answer.

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2 years ago

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Bingel [31]

The answer is x = 3

I hope this helped

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3 years ago