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Brrunno [24]
1 year ago
10

Need help with this question. only need help with A.

Mathematics
1 answer:
Oksi-84 [34.3K]1 year ago
6 0

The company gives the price of the new computer to be $2400.

If the company chooses to depreciate using the straight-line method over six years, the amount reduced per year will be:

\Rightarrow\frac{2400}{6}=400

Therefore, the linear function will be:

V(x)=2400-400x

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Lois has five blue plates and ten red plates what percent of her plate collection is blue
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There are 15 articles of clothing
5 are blue and 10 are red

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5 0
3 years ago
Find the area for a triangle that has a base of 24 inches and a height of 4 inches.
nirvana33 [79]

Answer:

48in²

Step-by-step explanation:

to find the area of a triangle you first divide the base by 2 then multiply it by the height

7 0
3 years ago
Simplify the next two expressions
prisoha [69]
1. 7x-40
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4 years ago
What is the sixth term of (a - y)7?<br><br> 21a3y4<br><br> -21a3y4<br><br> 21a2y5<br><br> -21a2y5
Katena32 [7]
Im guessing the fourth answer
3 0
3 years ago
Simplify this equation <br> Thanks a lot!!!
den301095 [7]

Answer:

-1

Step-by-step explanation:

We need to simplify the given expression . The given expression is ,

\rm\implies ( 2 \sqrt6 +5)^{2n-1} ( 2\sqrt6 - 5)^{2n-1}

Here we can see that the power of the both exponent is same that is (2n+1) . Recall the property of exponents ,

\bf\implies a^m \times b^m = (ab)^m

Using this property , we have ,

\rm\implies ( 2 \sqrt6 +5)^{2n-1} ( 2\sqrt6 - 5)^{2n-1}

This can be written as ,

\rm\implies\{( 2 \sqrt6 +5) ( 2\sqrt6 - 5)\}^{2n-1}

Simplifying using ( a+b)(a-b) = a² - b² ,

\rm\implies\{( 2 \sqrt6)^2 -5^2 \}^{2n-1}\\\\\rm\implies ( 24 - 25)^{2n-1}

Subtracting the numbers inside the brackets ,

\rm\implies (-1)^{2n - 1 }

Now we know that every odd number is in the form of 2n -1 , where n is any integer. Therefore , the <u>power is odd</u> .

Since the base is (-1) , for even power it is 1 and for odd power it is -1 . Therefore the final answer is ,

\rm\implies\boxed{\quad \red{ -1 }\quad }

<u>Hence </u><u>the</u><u> </u><u>required</u><u> answer</u><u> is</u><u> </u><u>(</u><u>-</u><u>1</u><u>)</u><u> </u><u>.</u>

4 0
3 years ago
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