The distance between two positions with longitudes A and B is given by ||A| - |B|| if the two positions are at the same side of the meridian (0 degrees longitude) and |A| + |B| if both positions are at different sides of the meridian.
Given that <span>Moscow is at 37.62 degrees longitude and Brasilia is at -47.87
degrees longitude, thus the two cities are at different sides of the meridian.
Therefore, the distance </span><span>(in degrees) between the longitude lines of Moscow and Brasilia</span> is |37.62| + |-47.87| = 37.62 + 47.87 = 85.49
Step-by-step explanation:
(Assuming that this triangle is isosceles)
If this triangle is isosceles, then x° is going to be equal to its twin angle; 40°.
We can solve for z now.
180 = 40 + 40 + z
180 = 80 + z
Subtract 80 from both sides.
100 = z
z = 100°
Now that we know z = 100 degrees, we can begin to solve the expression (3x -20)
The expression sits on a 180° line and the angle z (100°) shares the line with the expression (3x - 20)°
180 = 100 + (3x - 20)
Subtract 100 from both sides.
80 = 3x - 20
Add 20 to both sides to isolate 3x
100 = 3x
Divide by 3 on both sides.
100/3 = 3x/3
33.33... = x
it depends what the question is
steps:
total: 13 ppl
republicans: 4
1st person: 13-4/13 9/13
2nd person: 12-4/12 (because one person was taken out). 8/12
Answer:
0.1319 or 13.2%
Step-by-step explanation:
You can solve this using the binomial probability formula.
The fact that "obtaining at least two 6s" requires you to include cases where you would get three and four 6s as well.
Then, we can set the equation as follows:
P(X≥x) = ∑(k=x to n) C(n k) p^k q^(n-k)
n=4, x=2, k=2
when x=2 (4 2)(1/6)^2(5/6)^4-2 = 0.1157
when x=3 (4 3)(1/6)^3(5/6)^4-3 = 0.0154
when x=4 (4 4)(1/6)^4(5/6)^4-4 = 0.0008
Add them up, and you should get 0.1319 or 13.2% (rounded to the nearest tenth)