A. you are given that f(1)=5 therefore f(1) cannot also equal 1 unless it is a different equation.
Subtract 32 to both sides to the equation becomes -5x^2 + 7x + 9 = 0.
To solve this equation, we can use the quadratic formula. The quadratic formula solves equations of the form ax^2 + bx + c = 0
x = [ -b ± √(b^2 - 4ac) ] / (2a)
x = [ -7 ± √(7^2 - 4(-5)(9)) ] / ( 2(-5) )
x = [ -7 ± √(49 - (-180) ) ] / ( -10 )
x = [ -7 ± √(229) ] / ( -10)
x = [ -7 ± sqrt(229) ] / ( -10 )
x = 7/10 ± -sqrt(229)/10
The answers are 7/10 + sqrt(229)/10 and 7/10 - sqrt(229)/10.
Answer:

Step-by-step explanation:
1.Approach
To solve this problem, find the area of the larger circle, and the area of the smaller circle. Then subtract the area of the smaller circle from the larger circle to find the area of the shaded region.
2.Find the area of the larger circle
The formula to find the area of a circle is the following,

Where (r) is the radius, the distance from the center of the circle to the circumference, the outer edge of the circle. (
) represents the numerical constant (3.1415...). One is given that the radius of (8), substitute this into the formula and solve for the area,

3.Find the area of the smaller circle
To find the area of the smaller circle, one must use a very similar technique. One is given the diameter, the distance from one end to the opposite end of a circle. Divide this by two to find the radius of the circle.
8 ÷2 = 4
Radius = 4
Substitute into the formula,

4.Find the area of the shaded region
Subtract the area of the smaller circle from the area of the larger circle.


By counting grid squares, we see the library is 5 miles north and 6 miles east of Ashley's house. Using the Pythagorean theorem, we can find the straight-line distance to be
.. d = √(5^2 +6^2)
.. = √(25 +36)
.. = √61 . . . . . miles
.. ≈ 7.81 . . . . miles
14 out of 24 can be simplified to 7/12 which is 58.3%