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Deffense [45]
2 years ago
11

the dimensions of a block of stamps are 30 cm wide by 20 cm high. the same number of stamps could also have been arranged in a b

lock 24 cm wide. How high would this second block be?
Mathematics
1 answer:
adoni [48]2 years ago
6 0

Answer:The hight of such a stamp block would have to be 26 cm high by 24 cm wide

Step-by-step explanation: The way that i got my answer was by using this equation A+B=C

1.) 30cm+20cm=50cm

2.) 24cm+x=50cm

3.)50cm-24cm=x

4.)26cm=x

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The price of a computer was decreased by 30% to £147. What was the price before the decrease?
Sunny_sXe [5.5K]

Answer:

£210

Step-by-step explanation:

A decrease of 30% represents 70% of the original cost.

100% represents the original cost

Divide the price by 70 to find 1% then multiply by 100 for original cost

original cost = \frac{147}{70} × 100 = 2.1 × 100 = £210

4 0
3 years ago
Read 2 more answers
if the radius of one of the semi-circles is 7 meters what is the circumference of one of the semi-circles​
Yanka [14]

Answer:  43.96 m

Step-by-step explanation:

the circumference of one of the semi circle radius of one of the semicircles is 7 meters is 7 meters

ur welcome

3 0
2 years ago
If the circumference is 3/2 pi what is the area
11111nata11111 [884]

Here is your answer

\frac{9}{16} \pi \:  {units}^{2}

REASON:

Circumference(C)= 2πr

, where r is radius

Given

C= (3/2) π

So,

2\pi \: r =  \frac{3}{2}\pi

r =   \frac{\frac{3}{2}\pi}{2\pi}

r =  \frac{3}{4}

Now,

area = \pi {r}^{2}

= \pi \times  { (\frac{3}{4}) }^{2}

=  \frac{9}{16}\pi   \: {unit}^{2}

HOPE IT IS USEFUL

8 0
3 years ago
You coach a basketball ball team of 12 players; 5 players must be on the floor at all times; Figuring that every player can play
makvit [3.9K]
The function "choose k from n", nCk, is defined as
  nCk = n!/(k!*(n-k)!) . . . . . where "!" indicates the factorial

a) No position sensitivity.
The number of possibilities is the number of ways you can choose 5 players from a roster of 12.
  12C5 = 12*11*10*9*8/(5*4*3*2*1) = 792
You can put 792 different teams on the floor.

b) 1 of 2 centers, 2 of 5 guards, 2 of 5 forwards.
The number of possibilities is the product of the number of ways, for each position, you can choose the required number of players from those capable of playing the position.
  (2C1)*(5C2)*(5C2) = 2*10*10 = 200
You can put 200 different teams on the floor.
4 0
2 years ago
A random sample of 4"4 fields" of barley has a mean yield of "49.6"49.6 bushels per acre and standard deviation of 7.997.99 bush
ExtremeBDS [4]

Answer:

The critical value that should be used in constructing the interval is T = 5.8408.

The 99% confidence interval for the true mean yield is between 2.943 bushels per acre and 96.268 bushels per acre.

Step-by-step explanation:

We have the standard deviation of the sample, so we use the students t-distribution to solve this question.

The first step to solve this problem is finding how many degrees of freedom, we have. This is the sample size subtracted by 1. So

df = 4 - 1 = 3

99% confidence interval

Now, we have to find a value of T, which is found looking at the t table, with 3 degrees of freedom(y-axis) and a confidence level of 1 - \frac{1 - 0.99}{2} = 0.995. So we have T = 5.8408. This is the critical value.

The margin of error is:

M = T*s = 5.8408*7.99 = 46.668 bushels per acre

In which s is the standard deviation of the sample.

The lower end of the interval is the sample mean subtracted by M. So it is 49.6 - 46.668 = 2.943 bushels per acre.

The upper end of the interval is the sample mean added to M. So it is 49.6 + 46.668 = 96.268 bushels per acre.

The 99% confidence interval for the true mean yield is between 2.943 bushels per acre and 96.268 bushels per acre.

8 0
3 years ago
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