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choli [55]
1 year ago
7

Solve the unknown21​

Mathematics
2 answers:
nignag [31]1 year ago
8 0

Answer:

The trick to this problem is that first you have to subtract the digits and then add them. For example:

6 and 4, if we subtract them, we get 2 and if we add them, we get 10, therefore the answer is 210.

9 and 2, if we subtract them, we get 7 and if we add them, we get 11, therefore the answer is 711.

This works for the rest of the numbers as well and we can use it for the unknown problem

8 - 3 = 5

8 + 3 = 11

Therefore, the answer is 511

MakcuM [25]1 year ago
7 0

Answer:

\fbox{511}

<h3>Explanation:</h3>

6+4=(6 - 4)(6 + 4) = 210

9+2=(9  - 2)(9 + 2) = 711

8+5=(8 - 5)(8 + 5) = 313

3+2=(3 - 2)(3 + 2) = 15

following the same pattern,

8+3=(8 - 3)(8 + 3) = 511

\sf \small Thanks \:  for \:  joining \:  brainly  \: community!

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Step-by-step explanation:

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3 years ago
The science club went on a two day field trip. The first day the members paid $60 for transportation plus $15 to the planetarium
Dahasolnce [82]

Answer:

First day: $75

Second day: $107

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3 years ago
If 5 + 20 times 2 Superscript 2 minus 3 x Baseline = 10 times 2 Superscript negative 2 x Baseline + 5, what is the value of x? –
sp2606 [1]

Answer:

<h3>Option D) 3 is correct</h3><h3>Therefore the value of x is 3</h3>

Step-by-step explanation:

Given equation is 5+20\times (2)^{2-3x}=10\times (2)^{-2x}+5

<h3>To find the value of x :</h3>

First solving the given equation we have,

5+20\times (2)^{2-3x}=10\times (2)^{-2x}+5

5+20\times (2)^{2-3x}-5=10\times (2)^{-2x}+5-5

20\times (2)^{2-3x}=10\times (2)^{-2x}

20\times (2)^2.(2)^{-3x}=10\times (2)^{-2x}

20\times 4.(2)^{-3x}=10\times (2)^{-2x}

80(2)^{-3x}=10\times (2)^{-2x}

\frac{80}{10}(2)^{-3x}=\frac{10\times (2)^{-2x}}{10}

8(2)^{-3x}=(2)^{-2x}

\frac{(2)^{-3x}}{(2)^{-2x}}=\frac{1}{8}

(2)^{-3x}.(2)^{2x}=\frac{1}{2^3} ( by using the property \frac{1}{a^{-m}}=a^m )

2^{-3x+2x}=\frac{1}{2^3} ( by using the property a^m.a^n=a^{m+n} )

2^{-x}=\frac{1}{2^3}

\frac{1}{2^x}=\frac{1}{2^3} ( by using the property a^{-m}=\frac{1}{a^m} )

Since bases are same so powers are same

Therefore we can equate the powers we get x=3

<h3>Therefore the value of x is 3</h3><h3>Option D) 3 is correct</h3>
5 0
3 years ago
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Standard form 6000000+80000+10
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6,080,010 hope this helps you 

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