Answer:
31.4 in³
Step-by-step explanation:
The box is just big enough to hold the 3 balls, so it must have a length 6 times the radius of each ball, a width 2 times the radius, and a height 2 times the radius.
The volume of the box is:
V = (6r)(2r)(2r)
V = 24r³
The volume of the 3 balls is:
V = 3 (4/3 π r³)
V = 4πr³
So the volume of the air is:
V = 24r³ − 4πr³
V = (24 − 4π) r³
Since r = 1.4 inches:
V = (24 − 4π) (1.4 in)³
V ≈ 31.4 in³
I need points and i’m using this bc you didn’t even give an equation
Answer:
True
Step-by-step explanation:
Bcs, in the equation x+(-x)=0 you do x-x ( which is basically x+ -x) and they cancel each other out. This means your equation is 0=0
Answer:
m = 11
Step-by-step explanation:
11 - 5 = 6
(1)
f(x) + g(x) = 3x + 2 + 2x + 5 = 5x + 7
f(x) - g(x) = 3x + 2 - 2x - 5 = x - 3
(2)
f(x) + g(x) = 4x - 1 + 3x - 4 = 7x - 5
f(x) - g(x) = 4x - 1 - 3x + 4 = x + 3
(3)
f(x) + g(x) = - 5x + 3 + 2x - 4 = - 3x - 1
f(x) - g(x) = - 5x + 3 - 2x + 4 = - 7x + 7
(4)
f(x) + g(x) = 3x - 4 - 2x + 3 = x - 1
f(x) - g(x) = 3x - 4 + 2x - 3 = 5x - 7
(5)
f(x) × g(x) = - 2(- x + 7 ) = 2x - 14
(6)
f(x) × g(x) = - 5(2x - 7) = - 10x + 35
