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3 years ago

Darnell has

Mathematics

2 answers:

irinina [24]3 years ago

7 0

Answer:

the answer is 28

Step-by-step explanation:

345÷12=28.75

you can't have a 0.75 shirt

hodyreva [135]3 years ago

7 0

Answer:

Step-by-step explanation:

To get the number of shirts, you have to divide 345 by 12 which will give us 28.75.

so Darnell can complete 28 shirts with the buttons he has

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Suppose that $9500 is placed in an account that pays 8% interest compounded each year.

Blababa [14]

$\bf ~~~~~~ \textit{Compound Interest Earned Amount} \\\\ A=P\left(1+\frac{r}{n}\right)^{nt} \quad \begin{cases} A=\textit{accumulated amount}\\ P=\textit{original amount deposited}\dotfill &\$9500\\ r=rate\to 8\%\to \frac{8}{100}\dotfill &0.08\\ n= \begin{array}{llll} \textit{times it compounds per year}\\ \textit{each year, thus once} \end{array}\dotfill &1\\ t=years\dotfill &1 \end{cases}$

$\bf A=9500\left(1+\frac{0.08}{1}\right)^{1\cdot 1}\implies A=9500(1.08)\implies \boxed{A=10260} \\\\\\ \stackrel{\textit{after 2 years, t = 2}}{A=9500\left(1+\frac{0.08}{1}\right)^{1\cdot 2}}\implies A=9500(1.08)^2\implies \boxed{A=11080.8}$

6 0

2 years ago

Which shows the correct substitution of the values a, b, and c from the equation 0 = 4x2 + 2x – 1 into the quadratic formula bel

neonofarm [45]

Answer:

x = StartFraction negative 2 plus or minus StartRoot 2 squared minus 4(4)(negative 1) EndRoot Over 2(4) EndFraction

Step-by-step explanation:

we know that

The formula to solve a quadratic equation of the form

$ax^2+bx+c=0$

is equal to

$x=\frac{-b(+/-)\sqrt{b^2-4ac} }{2a}$

in this problem we have

$4x^2 + 2x - 1=0$

$a=4$

$b=2$

$c=-1$

substitute in the formula

$x=\frac{-2(+/-)\sqrt{2^2-4(4)(-1)} }{2(4)}$

therefore

x = StartFraction negative 2 plus or minus StartRoot 2 squared minus 4(4)(negative 1) EndRoot Over 2(4) EndFraction

8 0

1 year ago

Read 2 more answers

Find the missing side, then, round to the nearest tenth.<br> Looking for help with this problem!

jeka94

Answer:

4.6 = x the side opposite C would be 6.1

Step-by-step explanation:

you can use law of sine

you know you have a right triangle so the missing angle B = 49

4/sin41=x/sin49

4 0

2 years ago

Please help with this

Maksim231197 [3]

Answer:

Choice A

Step-by-step explanation:

SSS is not applicable as only 2 sides are congruent

HL is lot applicable as triangles are not right angled (∠A and ∠E >90)

ASA also not applicable as the angle should be included but is not

5 0

3 years ago

Match each series with the equivalent series written in sigma notation

PIT_PIT [208]

Answer:

$3 + 12 + 48 + 192 + 768 = \sum\limits^4_{n=0} 3 * 4^n$

$4 + 32 + 256 + 2048 + 16384 = \sum\limits^4_{n=0} 4 * 8^n$

$2 + 6 + 18 + 54 + 162 = \sum\limits^4_{n=0} 2* 3^n$

$3 + 15 + 75 + 375 + 1875 = \sum\limits^4_{n=0} 3* 5^n$

Step-by-step explanation:

Given

See attachment for complete question

Required

Match equivalent expressions

Solving (a):

$3 + 12 + 48 + 192 + 768$

The expression can be written as:

$3 \to 3*4^{0$ --- 0

$12 \to 3 * 4^{1$ ---- 1

$48 \to 3 * 4^{2$ --- 2

$192 \to 3 * 4^{3$ ---- 3

$768 \to 3 * 4^{4$ ---- 4

For the nth term, the expression is:

$Term = 3 * 4^{n$ ---- n

So, the summation is:

$3 + 12 + 48 + 192 + 768 = \sum\limits^4_{n=0} 3 * 4^n$

Solving (b):

$4 + 32 + 256 + 2048 + 16384$

The expression can be written as:

$4 \to 4 * 8^0$ --- 0

$32 \to 4 * 8^1$ ---- 1

$256 \to 4 * 8^2$ --- 2

$2048 \to 4 * 8^3$ ---- 3

$16384 \to 4 * 8^4$ ---- 4

For the nth term, the expression is:

$Term \to 4 * 8^n$ ---- n

So, the summation is:

$4 + 32 + 256 + 2048 + 16384 = \sum\limits^4_{n=0} 4 * 8^n$

Solving (c):

$2 + 6 + 18 + 54 + 162$

The expression can be written as:

$2 \to 2 * 3^0$ --- 0

$6 \to 2 * 3^1$ ---- 1

$18 \to 2 * 3^2$ --- 2

$54 \to 2 * 3^3$ ---- 3

$162 \to 2 * 3^4$ ---- 4

For the nth term, the expression is:

$Term \to 2 * 3^n$ ---- n

So, the summation is:

$2 + 6 + 18 + 54 + 162 = \sum\limits^4_{n=0} 2* 3^n$

Solving (d):

$3 + 15 + 75 + 375 + 1875$

The expression can be written as:

$3 \to 3 * 5^0$ --- 0

$15 \to 3 * 5^1$ ---- 1

$75 \to 3 * 5^2$ --- 2

$375 \to 3 * 5^3$ ---- 3

$1875 \to 3 * 5^4$ ---- 4

For the nth term, the expression is:

$Term \to 3 * 5^n$ ---- n

So, the summation is:

$3 + 15 + 75 + 375 + 1875 = \sum\limits^4_{n=0} 3* 5^n$

5 0

2 years ago