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KATRIN_1 [288]
3 years ago
7

8

Mathematics
1 answer:
STatiana [176]3 years ago
5 0

Answer:

(e^3 / e^2n)

Step-by-step explanation:

isn't this the same question

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19. Suppose 3 marbles are drawn without replacement from a bag containing 3 yellow and 4 white marbles. (a) Draw a histogram for
Alina [70]

Answer:

(a) see attachment

(b) E(x) = 226/105

Step-by-step explanation: see attachment

7 0
3 years ago
What is the value of x in the number 5/3+ 3x+4=8​
amm1812
5/3+3x+4= 8
= 3x= 4-5/3
= 3x= 7/3
= x= 7/9
4 0
2 years ago
Haley practiced her free throws at the basket ball court and shot 25 times. She made 11 of her shots. What percent of her shots
ivolga24 [154]

Answer:

<h2>56% </h2>

Step-by-step explanation:

Haley practiced her free throws at the basket ball court and shot 25 times

She made 11 of her shots.

find: What percent of her shots did she NOT make?​

<u>11 shots made</u>  = 44%

  25 shots

100% - 44% = 56%

therefore, 56% of her shot did NOT make it.

8 0
2 years ago
Wanda wants to buy a pair of shoes that cost $48 if sales tax is 8.25% what will be the total cost
lidiya [134]
48 x 8.25% = 3.96
Now add 3.96 + 48
Answer 51.96
3 0
3 years ago
From a random sample of size 18, a researcher states that (11.1, 15.7) inches is a 90% confidence interval for mu, the mean leng
alexandr402 [8]

Complete Question

From a random sample of size 18, a researcher states that (11.1, 15.7) inches is a 90% confidence interval for mu, the mean length of bass caught in a small lake. A normal distribution was assumed. Using the 90% confidence interval obtain:

a. A point estimate of \mu and its 90% margin of error.

b. A 95% confidence interval for \mu.

Answer:

a

\= x  = 13.4   .   E = 2.3

b

10.7 <  \mu < 16.1

Step-by-step explanation:

From the question we are told that

  The sample size is  n = 18

  The 90% confidence interval is  (11.1, 15.7)

Generally the point estimate of  \mu is mathematically  evaluated  as

       \= x  = \frac{11.1 + 15.7 }{2}

=>    \= x  = 13.4

Generally the margin of error is mathematically evaluated  as

     E = \frac{15.7 - 11.1}{2 }

=> E = 2.3

  From the question we are told the confidence level is  90% , hence the level of significance is    

      \alpha = (100 - 90 ) \%

=>   \alpha = 0.10

Generally from the normal distribution table the critical value  of  \frac{\alpha }{2} is  

   Z_{\frac{\alpha }{2} } =  1.645

Generally the equation for the lower limit of the confidence interval is  

      \= x  -  Z_{\frac{\alpha }{2} } * \frac{s}{\sqrt{18} } = 11.1

=> 13.4   -  0.3877 s  = 11.1

=>  s = 5.932

  From the question we are told the confidence level is  95% , hence the level of significance is    

      \alpha = (100 - 95 ) \%

=>   \alpha = 0.05

Generally from the normal distribution table the critical value  of  \frac{\alpha }{2} is  

   Z_{\frac{\alpha }{2} } =  1.96

Generally the margin of error is mathematically represented as  

      E = Z_{\frac{\alpha }{2} } *  \frac{\sigma }{\sqrt{n} }

=>    E =  1.96 *  \frac{5.932}{\sqrt{18} }

=>    E =  2.7      

Generally 95% confidence interval is mathematically represented as  

      \= x -E <  \mu <  \=x  +E

=>    13.4  -  2.7  <  \mu < 13.4  +   2.7

=>    10.7 <  \mu < 16.1

3 0
3 years ago
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