Answer:
<em>First even integer: 6</em>
Step-by-step explanation:
<u>Inequalities</u>
Assume x is the first even integer. The next integer is x+2, and the last integer ix x+4.
The condition states that the sum of the first and the second number is 15 less than three times the third. This takes us to the inequality:
Operating:
Subtracting 2 and 2x:
Simplifying:
Solving:
x>5
There are infinitely many solutions. For example, for x=6 (first even number into the solution interval):
First integer: 6
Second integer: 8
Third integer: 10
There are other solutions, like 20,22,24 but the first set is 6,8,10.
I would like to ask you to go to the vet, or attempt to, as this might be a worm in the eye. The same thing happened to my dog.
Answer:
29/18
Step-by-step explanation:
-11/6 + m = -2/9
Add 11/6 to both sides.
+11/6 -11/6 + m = -2/9 +11/6
m=29/18
To compare fractions, we need to have the same denominator
The least common multiple is
16
to change
, we should multiply the numerator and denominator by
4
=
<
so basically,
is greater than
which means
is greater
is greater
Approximately about $18,490
<span>PV= $15,000 </span>
<span>FV= solve for </span>
<span>PMT= 0 </span>
<span>I/YR= 7% </span>
<span>N= 36 </span>
<span>put these in your HP II calcu and you will get the approximate answer.
- b
e
x
t
e
m
(FAIL HARD)</span>
