Answer:
There are are 30 possible ways for the 6 students to be ranked 1st and 2nd
Step-by-step explanation:
There are 6 students, and any of them could receive first place. Therefore, there are 6 possibilities for first place.
A student cannot receive first and second place, so the student who won first place cannot also win second place. Therefore, there are only 5 students who could win second place.
We can multiply these two possibilities to find the number of possible rankings of 1st and 2nd
6*5=30
There are are 30 possible ways for the 6 students to be ranked 1st and 2nd....
Answer:
-25 and 2
Step-by-step explanation:
x + y = -23
xy = 50, so y = 50 /x
.
x + 50/x =-23, x^2 +23x - 50 = (x-2)(x+25)
so 2 and -25
Check the picture below
use the far-arc near-arc equation
bear in mind, your far-arc and near-arc are both in y-terms, so, the angle will be in y-terms as well
Because AB=RS=8m, ArcRS=Arc AB=ArcAR+ArcRB=55+66=121
The possible values (L,W): (1,7),(2,6),(3,5),(5,3),(6,2),(7,1)