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postnew [5]
3 years ago
10

For each of the following quadrilaterals, Select all the properties that must be true.

Mathematics
1 answer:
OleMash [197]3 years ago
8 0

Answer:

1) two pairs of parallel sides

2) four right angles and all sides congruent

3) all sides congruent

Step-by-step explanation:

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Find the square. (1/4A + 1/4B)^2<br><br> a) 1/16A^2 + 1/8AB + 1/16B^2<br> b) 1/4A^2 + 1/8AB + 1/4B^2
alisha [4.7K]

(a + b)^2 = a^2 + 2ab + b^2

(\dfrac{1}{4}A + \dfrac{1}{4}B)^2 =

= \dfrac{1}{16}A^2 + \dfrac{1}{8}AB + \dfrac{1}{16}B^2

Answer: A.

Another way to solve by factoring 1/4.

(\dfrac{1}{4}A + \dfrac{1}{4}B)^2 =

= [\dfrac{1}{4}(A + B)]^2

= (\dfrac{1}{4})^2(A + B)^2

= \dfrac{1}{16}(A^2 + 2AB + B^2)

= \dfrac{1}{16}A^2 + \dfrac{1}{16}2AB + \dfrac{1}{16}B)^2

= \dfrac{1}{16}A^2 + \dfrac{1}{8}AB + \dfrac{1}{16}B)^2

6 0
4 years ago
Read 2 more answers
A number that is prime, between 60-100,1s place is 2 less then 10s place.
Crank
The answer to that would be 97.

Hope this helps! :)
7 0
4 years ago
2) 83,97,85,84,96, 80,80,87,91<br> Mean median and mode
marusya05 [52]

\text {Hi! Let's Solve this Problem!}

\text {Before you find the Mean, Medina and Mode you must put the numbers in order.}

\text {Before: 83, 97, 85, 84, 96, 80, 80, 87, 91}\\\text {After: 80, 80, 83, 84, 85, 87, 91, 96, 97}

\underline {\text {Mean}}

\text {To Find the Mean you must Add all the Numbers then Divide.}

\text {Add:} \text 80+80+83+84+85+87+91+96+97=\fbox {783}}

\text {Divide:} \text {783/9=}

\text {The Mean Is:}

\fbox {87}

\underline {\text Median}}

\text {To find the Median you find the number that's in the middle of the set.}

\text {Put your Left Pointer Finger on 83. Put your Right Pointer Finger on 91.}

\text {Move your Left Finger to the Right. Move your Right Finger to the Left.}

\text {Once your Left Finger makes it to 84 and your Right Finger makes it to 87} \text {it shows that 85 is left in the middle.}

\text {The Median Is:}

\fbox {85}

\underline {\text {Mode}}

\text {Finding the Mode means finding the number} \text { that shows the most in the number set given.}

\text {Since 80 is the number that is showing more than any other number} \text {this tells us that 80 is our Mode.}

\text {The Mode Is:}

\fbox {80}

\text {Best of Luck!}

4 0
4 years ago
What is the product of seven and eight decreased by “x” if x =15?
jekas [21]

Answer:

0

Step-by-step explanation:

product is another word for +

decreased is another word for -

____________________________

(7 + 8) - x

so

(7+8) - 15

15 - 15

= 0

7 0
3 years ago
Read 2 more answers
Six divided by three fifths
Slav-nsk [51]
The answer is 10. I hope that this helped ☻
3 0
3 years ago
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