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lidiya [134]
1 year ago
7

Determine whether quadrilateral ABCD is a rhombus, a rectangle, a square, a parallelogram, or none. List all that apply. Explain

.
--
Help pls? anyone :(?

Mathematics
1 answer:
svlad2 [7]1 year ago
5 0

Answer:

  • ABCD is a rhombus, and a parallelogram

==================================

<h3>Given </h3>

  • Points A(-6, - 1), B(4, - 6), C(2, 5), D(- 8, 10)

First, plot the points (see attached picture).

Then, connect all the points.

<h3>We see that:</h3>

  • Opposite sides are parallel,
  • Diagonals are perpendicular.

From our observation the figure is rhombus.

Let's confirm it with the following.

1) Find midpoints of diagonals and compare.

  • AC → x = (- 6 + 2)/2 = - 2, y = (- 1 + 5)/2 = 2
  • BD → x = (4 - 8)/2 = - 2, y = (- 6 + 10)/2 = 2

The midpoint of both diagonals is same (- 2, 2).

2) Find slopes of diagonals and check if their product is -1, this will confirm they are perpendicular.

  • m(AC) = (5 - (-1))/(2 - (-6)) = 6/8 = 3/4
  • m(BD) = (10 - (-6))/(-8 - 4) = - 16/12 = - 4/3

  • m(AC) × m(BD) = 3/4 * (- 4/3) = - 1

<u>Confirmed.</u>

So this is a rhombus and also a parallelogram but <u>not</u> rectangle or square, since opposite angles are not right angles.

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What is an equation of the line that passes through the point (-6,-8) and is parallel to the line x-2y=6?
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Answer:

y=\frac{1}{2}x-5

Step-by-step explanation:

Hi there!

<u>What we need to know:</u>

  • Linear equations are typically organized in slope-intercept form: y=mx+b where m is the slope and b is the y-intercept (the value of y when the line crosses the y-axis)
  • Parallel lines always have the same slope and different y-intercepts

<u>1) Determine the slope (m)</u>

x-2y=6

Rearrange this equation into slope-intercept form (this will help us find the slope)

Subtract x from both sides

x-2y-x=6-x\\-2y=-x+6

Divide both sides by -2

y=\frac{1}{2} x-3

Now, we can identify clearly that the slope of the given line is \frac{1}{2} since it's in the place of m. Because parallel lines always have the same slopes, the line we're currently solving for would therefore have a slope of \frac{1}{2} as well. Plug this into y=mx+b:

y=\frac{1}{2}x+b

<u>2) Determine the y-intercept (b)</u>

y=\frac{1}{2}x+b

Plug in the given point (-6,-8)

-8=\frac{1}{2}(-6)+b\\-8=-3+b

Add 3 to both sides to isolate b

-8+3=-3+b+3\\-5=b

Therefore, the y-intercept is -5. Plug this back into y=\frac{1}{2}x+b:

y=\frac{1}{2}x-5

I hope this helps!

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3 years ago
Who can help me with this for algebra 2
Anuta_ua [19.1K]
The answer to this equation is

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