Answer:
what do you want me to help you with cuz there's nothing attached??
Step-by-step explanation:
Step-by-step explanation:
Well, to be perfectly honest in my humble opinion, of course without offending anyone who thinks different from my point of view but also by looking into this matter in a different perspective and without condemning one's view and by trying to make it objectified and considering each and everyone's valid opinion, I honestly believe that I completely forgot what I was going to say.
Answer:
Yes.
Step-by-step explanation:
Just like normal algebra, you factor our the common factor, in this case, 5.
Thus,
Answer:
- The square root and quadratic function share a y-intercept.
- The range of the square root and absolute value function are the same.
Step-by-step explanation:
Y-intercepts are the same when the curves meet the y-axis at the same point. That is true of the root and quadratic functions.
X-intercepts are the same when the curves meet the x-axis at the same point. None of these functions share an x-intercept.
The ranges of the functions are the same when they have the same vertical extent. The range of the quadratic is different from the range of the other two functions.
The absolute value and root functions have the same minimum (lower end of their range). That is the same as the maximum of the quadratic function.
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The statements that match the graphs are ...
- The square root and quadratic function share a y-intercept.
- The range of the square root and absolute value function are the same.
Answer:
therefore y= - (x-2)^2 + 5
Step-by-step explanation:
u do this by using this format here ..,
y=a(x-h)^2+k
sub in the vertex points as h=2 and k = 5 , since the 2 is positive its sign will be -2 in the brackets because when solving for x-2=0 it is x=2
y=a(x-2)^2+5
then with your (0,1) points plug that in as y and x
1=a(0-2)^2+5
1=a(-2)^2+5
1=4a+5
1-5=4a
-4=4a
a=-1
therefore y= - (x-2)^2 + 5
