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dlinn [17]
2 years ago
5

HELP ME PLEASE, WILL MARK BRAINLIEST

Mathematics
1 answer:
kifflom [539]2 years ago
3 0

The height of the arrow at 2.5 seconds is 71 feet.

Given:

An arrow released from a bow, traveling towards a target 200 yards away,reaches a max height of 42.6 ft in only 1.5 seconds.

1.5 seconds = 42.6 feet

divide by 1.5 on both sides.

1 sec = 28.4 feet

0.5 sec = 28.4/2

0.5 sec = 14.2 feet

2.5 sec = 1.5 sec + 1 sec

= 42.6 + 28.4

= 71 feet

Therefore The height of the arrow at 2.5 seconds is 71 feet.

Learn more about the max height here:

brainly.com/question/22564953

#SPJ1

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Question 6
ad-work [718]

Answer:

The input for the method is a continuous function f, an interval [a, b], and the function values f(a) and f(b). The function values are of opposite sign (there is at least one zero crossing within the interval). Each iteration performs these steps: Calculate c, the midpoint of the interval, c = a + b2.

Step-by-step explanation:

trust

7 0
3 years ago
Your friend shows you a coin collection. 35/50 (35 out of 50) of those coins are quarters. What percent of the coins are quarter
Natasha2012 [34]
70% of the coins are quarters

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3 0
3 years ago
How do i Evaluate this expression?​
timofeeve [1]

\text{Hey there!}

\bf{9.83+8.2(7.01)}

\text{You could solved this equation by doing PEMDAS}

\text{PEMDAS simply means}\downarrow

\text{Parentheses }

\text{Exponents}

\text{Multiplication}

\text{Division}

\text{Addition}

\text{Subtraction}

\text{In your equation you have \bf{MULTIPLICATION \& ADDITION}}

\text{Now,  that we have every information we need.. lets solve the problem}

\text{We have to do \underline{MULITPLICATION} first then \underline{ADDITION} last}

\text{9.83 + 8.2(7.01)}

\text{8.2(7.01)=57.482}

\text{9.83 + 57.482 = 67.312}

\boxed{\boxed{\text{Thus your answer is most likely: \bf{67.312}}}}\checkmark

\text{Good luck on your assignment and enjoy your day!}

~\frak{LoveYourselfFIrst:)}

3 0
3 years ago
Point G is on line segment FH. Given FG=5x+2,GH=3x-1, and FG=9, determine the numerical length of FG
stealth61 [152]

Given:

FG=5x+2

GH=3x-1

FG=9

Let us draw the line segment as follows,

Equating the length of FG, we get,

\begin{gathered} 5x+2=9 \\ 5x=9-2 \\ 5x=7 \\ x=\frac{7}{5} \end{gathered}

Substitute the value of x in the given value of GH,

\begin{gathered} GH=3x-1 \\ =3(\frac{7}{5})-1 \\ =\frac{21}{5}-1 \\ =\frac{16}{5} \\ =3.2 \end{gathered}

And the total length FH is,

\begin{gathered} FH=FG+GH \\ =9+3.2 \\ =12.2 \end{gathered}

Hence, the lengths are,

\begin{gathered} FG=9 \\ GH=3.2 \\ FH=12.2 \end{gathered}

8 0
1 year ago
I need help with part B
lys-0071 [83]
Okay, well with the information given, you can not come to an answer.  Is there something that shows all of the students who were in the survey?

Edit: Okay so there are 520 students in total.

We can say that the graph is equal to 520/520

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Now, we can find 15% of 520 by taking 15/100 times 520.  The answer is 78.
3 0
4 years ago
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