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11 months ago

HELP ME PLEASE, WILL MARK BRAINLIEST

Mathematics

1 answer:

kifflom [539]11 months ago

3 0

The height of the arrow at 2.5 seconds is 71 feet.

Given:

An arrow released from a bow, traveling towards a target 200 yards away,reaches a max height of 42.6 ft in only 1.5 seconds.

1.5 seconds = 42.6 feet

divide by 1.5 on both sides.

1 sec = 28.4 feet

0.5 sec = 28.4/2

0.5 sec = 14.2 feet

2.5 sec = 1.5 sec + 1 sec

= 42.6 + 28.4

= 71 feet

Therefore The height of the arrow at 2.5 seconds is 71 feet.

Learn more about the max height here:

brainly.com/question/22564953

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