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ddd [48]
3 years ago
6

How many solutions are there? 100pts

Mathematics
2 answers:
Maurinko [17]3 years ago
8 0

\\ \rm\Rrightarrow 5(2b+1)=10b+5

\\ \rm\Rrightarrow 10b+5=10b+5

\\ \rm\Rrightarrow 0=0

  • Infinite solutions
ra1l [238]3 years ago
4 0

Answer:

infinite many solutions

Step-by-step explanation:

  • 5(2(b)+1) = 10(b) + 5
  • 10(b) + 5 = 10(b) + 5

<u>As L.H.S = R.H.S, there are infinite many solutions</u>

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max2010maxim [7]

Answer:

\displaystyle \sin\left(2\sec^{-1}\left(\frac{u}{10}\right)\right)=\frac{20\sqrt{u^2-100}}{u^2}\text{ where } u>0

Step-by-step explanation:

We want to write the trignometric expression:

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