The graph of g(x) would look the same as the given graph, EXCEPT that it'd be compressed by a factor of 1/3. Try graphing both f(x) and g(x) on your calculator and then comparing the 2 graphs.
the Pythagorean Theoremproof of let ΔABC be a right triangle. and sinA=a/c, and cosA= b/ca opposite side of the angle Ab the adjacent side of the angle Aand c is the hypotenuswe know that sin²A +cos²A= (a/c)²+ (b/c) ², but sin²A +cos²A=1so, a²/c²+ b²/c ²=1 which implies a²+ b²=c² the answer is Transitive Property of Equality proof the right triangles BDC and CDA are siWe start with the original right triangle, now denoted ABC, and need only one additional construct - the altitude AD. The triangles ABC, DBA, and DAC are similar which leads to two ratios:AB/BC = BD/AB and AC/BC = DC/AC.Written another way these becomeAB·AB = BD·BC and AC·AC = DC·BCSumming up we getAB·AB + AC·AC= BD·BC + DC·BC = (BD+DC)·BC = BC·BC.so not in the proof is Transitive Property of Equality
Perfect-square trinomials are of the form:
and are expressed in squared-binomial form as: 
The only possible choice for squared-binomial form is
Answer: correct choice is A.
Answer:
11
Step-by-step explanation:
Hope it helps you :)
"Mr. Bombastic, tell me fantastic. Touch me
na me back. She says I'm mister r00000-
mantic, call me fantastic. Touch me na me
back. She says I'm Mr. Ro- Smooooth" - Biggie
Cheese
