( –6m^7 + 20m^6<span>) ÷ 2m^4 = ???
as you know
</span> –6m^7 + 20m^6 = 2m^4 (-3m^3 + 10m^2)
[2m^4 (-3m^3 + 10m^2) ] / 2m^4 (2m^4 is canceled out)
= -3m^3 + 10m^2
answer is B. –3m^3 + 10m^2
In below formula for arithmetic sequence you can fill in a=7 (start), d=2 (interval) and n=35 (nr terms) and you get
17.5(14 + 34*2) = 1435
Confirmed by a brute-force addition: 7+9+11+13+15+17+19+21+23+25+27+29+31+33+35+37+39+41+43+45+47+49+51+53+55+57+59+61+63+65+67+69+71+73+75=1435
<span>To remove any negative sign in front of a number, and to think of all numbers as positive (or zero). Example: |5|=5</span>
What you want to do is cross multiply so you get 5(x+4)=7(3x+28) then you distrubute the 5 and then you distribute the 5 and the 7 to the number in the parentheses 5x+20=21x+196
subtract 5x on both sides to get 20=16x+196 then you subtract 196 on both sides to get -176=16x last what you want to do is divide 16 on both sides to get x=-11
