I like A as the best one
420 = 100*price - (fixed costs)
220 = 60*price - (fixed costs)
If we subtract one from the other one, we get 200 = 40*price, price = 5
that said, fixed costs are 500 - 420 = 80
Now if we move -220 to the right in Answer A, we'll get:
y = 5x -300 + 220 = 5x - 80
So it looks like A describes the model best
Answer:
A) (1 s, 2.3 s)
B) (-4 m/s², 3.8 m/s²)
Step-by-step explanation:
The car's position which is the distance is given by the equation;
s(t) = t³ - 5t² + 7t
A) Velocity is the first derivative of the distance. Thus;
v(t) = ds/dt = 3t² - 10t + 7
At v = 0, we have;
3t² - 10t + 7 = 0
Using quadratic formula, we have;
t = 1 and t = 2.3
Thus, time at velocity of 0 is t = (1 s, 2.3 s)
B) acceleration is the derivative of the velocity. Thus;
a(t) = dV/dt = 6t - 10
At velocity of 0, we got t = 1 and t = 2.3
Thus;
a(1) = 6(1) - 10 = -4 m/s²
a(2.3) = 6(2.3) - 10 = 3.8 m/s
Thus, a(t) at v = 0 gives; (-4 m/s², 3.8 m/s²)
Start with
Expand both parentheses by multiplying both terms by the number outside:
Sum like terms:
Simplify the "+3" on both sides:
Subtract 2x from both sides:
Divide both sides by 2:
9 5/6+5 1/6= 14 6/6=15
Most Simplified Answer: 15
Answer:
The two numbers marked on the number line are -5 and 7.
Two inequalities to compare the marked numbers on the number line:
-5 < 7 or 7 > -5
The <u><em>written form</em></u> of the two inequalities are:
-5 < 7 : Negative five is <u>less than</u> positive seven.
7 > -5 : Positive seven is <u>greater than</u> negative five.
