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Juli2301 [7.4K]
1 year ago
13

A spinner is divided into four equal sections that are numbered 2, 4, 7, and 9. The spinner is spun twice.How many outcomes have

a product less than 30 and contain at least one odd number? A. 5B. 6C. 8D. 10
Mathematics
1 answer:
Alexxx [7]1 year ago
5 0

First, we compute all of the possible results:

(2,2), (2,4), (2,7), (2,9), (4,2), (4,4), (4,7), (4,9), (7,2), (7,4), (7,7), (7,9), (9,2), (9,4), (9,7), (9,9).

Notice that the pair of ressults which its product is less than 30 are:

(2,2),(2,4), (2,7), (2,9), (4,2), (4,4),(4,7),(7,2), (7,4), (9,2).

From the pairs above those from which at least 1 of the numbers is odd are:

(2,7), (2,9), (4,7), (7,2), (7,4), (9,2).

Answer: 6.

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3 years ago
What is 1/4(9y-3)+1/8(6y+9) simplified?
dusya [7]

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3y+3\8

Step-by-step explanation:

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Pls help me asap!!!!
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I believe that it is C, mind you I could’ve got it wrong. It’s been awhile since I’ve done that kind of math.
6 0
3 years ago
F(x)=3x2+2x−3 <br><br> g(x)=2x+4
Yakvenalex [24]

Answer:

A: 6

B: 16

C: 2

D: -12

Step-by-step explanation:

They are asking you to multiply the equations:

(3x^2 + 2x - 3)(2x + 4)

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6x^3 + 16x^2 + 2x - 12

The Coefficients A,B,C, and D are 6, 16, 2, and -12.

3 0
3 years ago
(3 points) Determine whether each of these functions f : {a, b, c, d} → {a, b, c, d} is one-to-one and whether each of these fun
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Answer:

Step-by-step explanation:

Recall the following. Given a function f we say that  

f is one to one if for x,y in the domain of f and f(x)=f(y) then x=y.

This means that there are no different elements in the domain of the function  that are linked to the same value.

f is onto if for every y in the codomain of f, then there is an element x in the domain of f such that f(x) = y. That is, given an element y in the codomain of f, there exists and element in the domain that is linked to y.

a)  

f(a) =b, f(b)=a, f(c) = c, f(d) = d. Note that this function links each element in {a,b,c,d} to different elements in {a,b,c,d}, so it is a one to one function. Since for every element x in {a,b,c,d} there is an element y in {a,b,c,d} such that f(y) = x, then this function is also onto.  

b)  

f(a)=b, f(b) = b, f(c) = d, f(d) = c. Note that the elements a,b are linked both to b, so this function fails to be one-to-one. Also, note that the element a has no element x in {a,b,c,d} such that f(x) = a, so this function fails to be onto.  

c)  

f(a) = d, f(b) = b, f(c) = c, f(d) = d.  

As in b), since a and d are linked to d, then this function is not one to one. Also, since the element a has no element x in {a,b,c,d} such that f(x) = a, then it also fails to be onto.  

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3 years ago
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