4 years ago

Help me please, ill give u the brainlest thing

Mathematics

1 answer:

gogolik [260]4 years ago

8 0

Wouldn’t it be 180° I’m not sure but I’m pretty sure that it’s a reflection

You might be interested in

Valerie roller-skated 4 miles at an average speed of 8 mph. She started her skate at 4:15 p.m.

Gre4nikov [31]

4 miles
8 miles per hour
4/8=1/2
skated for 1/2 hour
1/2 times 60=30
4:15+30=4:45

answer is D

8 0

4 years ago

Classify the polynomial based on number of terms - z6 + 3z5 + 5z4 - 1

Llana [10]

It’s a quartic polynomial double check but I think that’s what it is

5 0

2 years ago

is the measure of how much the values in a data set vary, or deviate, from the mean; it tells us how spread out the data is from

Aleonysh [2.5K]

Answer:rr

Step-by-step explanation:

3 0

4 years ago

Read 2 more answers

Don opened a checking account. Let F represent the

Law Incorporation [45]

Answer:

B and E

Step-by-step explanation:

In the function f(m)= -50m+300

-50 is the gradient meaning it is the rate of change per month. This means that the rate of change is -50 since this is the coefficient of m.

Also, -50m must be negative since m represents a month and you cant have negative months, so you know that the amount of money is decreasing

6 0

4 years ago

Playland park charges 7 dollars admission plus 75 crnts per ride. Funland park charges 12.50$ admission plus 50 cents per ride.

WINSTONCH [101]

Answer:

22 rides

Step-by-step explanation:

Both the parks has a fixed cost (admission fee) and a variable cost (per ride cost). We can model 2 equations in "x" [let x be number of rides], equate them and find "x".

<u>Playland Park:</u>

Fixed Cost = 7

Variable Cost = 0.75x (in dollars)

Equation = 7 + 0.75x

<u>Funland Park:</u>

Fixed Cost = 12.50

Variable Cost = 0.50x (in dollars)

Equation = 12.50 + 0.50x

Now we equate and solve for x:

$7+0.75x=12.50 + 0.50x\\0.75x-0.50x=12.50-7\\0.25x=5.50\\x=\frac{5.50}{0.25}\\x=22$

Hence,

the cost would be same for both parks for 22 rides

8 0

4 years ago