let "a number" = x
a number is divided by 3 => x/3
14 is added to the quotient => (x/3) + 14
The result is 33 => " = 33"
Solve for x
(x/3) + 14 = 33
Isolate the x. Note the equal sign. What you do to one side you do the other.
Subtract 14 from both sides
(x/3) + 14 (-14) = 33 (-14)
x/3 = 19
Isolate the x. Multiply 3 to both sides
x/3(3) = 19(3)
x = 19(3)
x = 57
57 is your original number
hope this helps
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f(x)= -0.4x+107
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A^-1:B^-1
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im not 100% sure but i think this is the right answer :)
