Question

What is the perimeter of this rectangle?

Answer 1

We will have the following:

First, we can see that the perimeter of the rectangle will be given by:

$\begin{gathered} p=2\sqrt{(y_2-y_1)^2+(x_1-x_1)^2}+2\sqrt{(y_2-y_2)^2+(x_2-x_1)^2} \\ \\ \Rightarrow p=2\sqrt{(y_2-y_1)^2}+2\sqrt{(x_2-x_1)^2} \\ \\ \Rightarrow p=2(y_2-y_1)+2(x_2-x_1) \end{gathered}$

So, we can see that the perimeter of the shape is option A.