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2 years ago

What is the volume of the figure?

Mathematics

2 answers:

Naddik [55]2 years ago

6 0

D think so hope this helps you and sorry for the late anwer

snow_tiger [21]2 years ago

5 0

A the answer is 1296 but 756 is squared so it is A ok thats easy i did that in 7th grade finally something i can do

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Two numbers are opposites are 12 units apart. What are the two numbers? Answer smaller number, larger number

Ugo [173]

Answer:

-6, 6

Explanation:

-6 - 6 = -12

8 0

2 years ago

Find the product of (x – a) and (x - b).

yawa3891 [41]

(x−a)(x−b)

=(x+−a)(x+−b)

=(x)(x)+(x)(−b)+(−a)(x)+(−a)(−b)

=x2−bx−ax+ab

6 0

3 years ago

The Zurn family ate at a restaurant that was having a 15% discount on that day.Their meal costs $64.75,and they left a 20% tip.W

My name is Ann [436]

Answer:C

Step-by-step explanation:

4 0

3 years ago

A population of values has a normal distribution with μ=204.9μ=204.9 and σ=81.9σ=81.9. You intend to draw a random sample of siz

marin [14]

Answer:

7. μ=204.9 and σ=5.4968

8. μ=75.9 and σ=0.7136

9. p=0.9452

Step-by-step explanation:

7. - Given that the population mean =204.9 and the standard deviation is 81.90 and the sample size n=222.

-The sample mean, $\mu_x$ is calculated as:

$\mu_x=\mu=204.9, \mu_x=sample \ mean$

-The standard deviation, $\sigma_x$ is calculated as:

$\sigma_x=\frac{\sigma}{\sqrt{n}}\\\\=\frac{81.9}{\sqrt{222}}\\\\=5.4968$

8. For a random variable X.

-Given a X's population mean is 75.9, standard deviation is 9.6 and a sample size of 181

-#The sample mean, $\mu_x$ is calculated as:

$\mu_x=\mu\\\\=75.9$

#The sample standard deviation is calculated as follows:

$\sigma_x=\frac{\sigma}{\sqrt{n}}\\\\=\frac{9.6}{\sqrt{181}}\\\\=0.7136$

9. Given the population mean, μ=135.7 and σ=88 and n=59

#We calculate the sample mean;

$\mu_x=\mu=135.7$

#Sample standard deviation:

$\sigma_x=\frac{\sigma}{\sqrt{n}}\\\\=\frac{88}{\sqrt{59}}\\\\=11.4566$

#The sample size, n=59 is at least 30, so we apply Central Limit Theorem:

$P(\bar X>117.4)=P(Z>\frac{117.4-\mu_{\bar x}}{\sigma_x})\\\\=P(Z>\frac{117.4-135.7}{11.4566})\\\\=P(Z>-1.5973)\\\\=1-0.05480 \\\\=0.9452$

Hence, the probability of a random sample's mean being greater than 117.4 is 0.9452

7 0

3 years ago

You have been tasked with filling 4 ounce and 3 ounce bags from a 41 ounce container of candy.

Alchen [17]

Answer:

A. 3 possible combinations

B. 8 4-ounce's bags and 3 3-ounce's bags

C. 2 4-ounce's bags and 11 3-ounce's bags

D. 8 4-ounce's bags and 3 3-ounce's bags

E. All solutions offer the same revenue.

Step-by-step explanation:

You have been tasked with filling 4 ounce and 3 ounce bags from a 41 ounce container of candy. Let x be the number of 4 ounce bags and y be the number of 3 ounce bags. Then

$4x+3y=41.$

A. Find all integer solutions:

When x=0, then 3y=41 - impossible, because 41 is not divisible by 3.

When x=1, then 3y=37 - impossible, because 37 is not divisible by 3.

When x=2, then 3y=33, y=11 - possible.

When x=3, then 3y=29 - impossible, because 29 is not divisible by 3.

When x=4, then 3y=25 - impossible, because 25 is not divisible by 3.

When x=5, then 3y=21, y=7 - possible.

When x=6, then 3y=17 - impossible, because 17 is not divisible by 3.

When x=7, then 3y=13 - impossible, because 13 is not divisible by 3.

When x=8, then 3y=9, y=3 - possible.

When x=9, then 3y=5 - impossible, because 5 is not divisible by 3.

When x=10, then 3y=1 - impossible, because 1 is not divisible by 3.

You get 3 possible combinations.

B. 1. 2 + 11 = 13,

2. 5 + 7 = 12,

3. 8 + 3 = 11.

The minimal number of bags is 11.

C. 1. 2·7+11·5=69 cents

2. 5·7+7·5=70 cents

3. 8·7+3·5=71 cents

The cheapest is 1st solution.

D. 1. 2·6+11·5=67 cents

2. 5·6+7·5=65 cents

3. 8·6+3·5=63 cents

The cheapest is 3rd solution.

E. 1. 2·2+11·1.50=$20.50

2. 5·2+7·1.50=$20.50

3. 8·2+3·1.50=$20.50

All solutions offer the same revenue.

5 0

2 years ago