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FinnZ [79.3K]
1 year ago
7

Graph the line with slope −1/2 and y-intercept −5.

Mathematics
1 answer:
Allushta [10]1 year ago
5 0

First, we can write the equation of the line using the information provided:

\begin{gathered} y=mx+b \\ where: \\ m=slope=-\frac{1}{2} \\ b=y-intercept=-5 \\ so: \\ y=-\frac{1}{2}x-5 \end{gathered}

Now, we can create a table:

Finally, we can graph the line:

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The function u(x)=-x+3x^{2} -8 is a quadratic function due to the highest exponent being 2.

Given functions are:

u(x)=-x+3x^{2} -8

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y(x)=x^{2} +3x^5+4

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<h3>What is a quadratic function?</h3>

A function of the form f(x)=ax^{2} +bx+c with a\neq 0 is called a quadratic function means the highest exponent of polynomial should be 2.

Let us check one by one.

u(x)=-x+3x^{2} -8

Highest exponent =2

The function is also of form f(x)=ax^{2} +bx+c so u(x) is a quadratic function.

The functions v(x), y(x), and z(x) are having highest exponents as 3,5, and 3 respectively so they are not quadratic functions.

Hence, the function u(x)=-x+3x^{2} -8 is a quadratic function due to the highest exponent being 2.

To get more about quadratic functions visit:

brainly.com/question/1214333

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