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1 year ago

Graph the line with slope −1/2 and y-intercept −5.

Mathematics

1 answer:

Allushta [10]1 year ago

5 0

First, we can write the equation of the line using the information provided:

$\begin{gathered} y=mx+b \\ where: \\ m=slope=-\frac{1}{2} \\ b=y-intercept=-5 \\ so: \\ y=-\frac{1}{2}x-5 \end{gathered}$

Now, we can create a table:

Finally, we can graph the line:

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2/3 of ___=6<br> Can you help me?

Artyom0805 [142]

9 is the answer because 1/3 = 3

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3 years ago

Read 2 more answers

The diagram shows the entrance to a tunnel.

gladu [14]

Step-by-step explanation:

it filled up half the circle (up to the center point) - if we had a full circle. but a little bit is cut off (below AB).

what we see is that the shaded area is the sum of the area of the triangle AOB and 2 equally sized circle segment areas left and right of AOB.

since we are dealing with a half-circle, we have 180° in total. 120° are taken by AOB, so, that leaves us with 180-120 = 60° for both circle segments (so, one has an angle of 30°).

and 2×30° = 1×60°, so we can calculate the area of one 60° segment instead of two 30° segments.

AOB is an isoceles triangle (the legs are equally long, and therefore also the 2 side angles are equal).

the area of this triangle AOB is

1/2 × a × b × sin(C) = 1/2 × 3 × 3 × sin(120) =

= 3.897114317... m²

a circle segment area of 60° is 60/360 = 1/6 of the full circle area (as a full circle = 360°).

so, it's area is

pi×r² × 1/6 = pi×3²/6 = pi×3/2 = 4.71238898... m²

so, the total area of the shaded area is

3.897114317... m² + 4.71238898... m² =

= 8.609503297... m²

5 0

2 years ago

Suppose that a college determines the following distribution for X = number of courses taken by a full-time student this semeste

lidiya [134]

Answer:

$E(X) = \sum_{i=1}^n X_i P(X_i) = 3*0.07 +4*0.4 +5*0.25 +6*0.28= 4.74$ In order to find the variance we need to calculate first the second moment given by:

$E(X^2) = \sum_{i=1}^n X^2_i P(X_i) = 3^2*0.07 +4^2*0.4 +5^2*0.25 +6^2*0.28= 23.36$ And the variance is given by:

$Var(X) = E(X^2) +[E(X)]^2 = 23.36 -[4.74]^2 = 0.8924$

And the deviation would be:

$Sd(X) =\sqrt{0.8924} =0.9447$

Step-by-step explanation:

Previous concepts

The expected value of a random variable X is the n-th moment about zero of a probability density function f(x) if X is continuous, or the weighted average for a discrete probability distribution, if X is discrete.

The variance of a random variable X represent the spread of the possible values of the variable. The variance of X is written as Var(X).

Solution to the problem

For this case we have the following distribution given:

X 3 4 5 6

P(X) 0.07 0.4 0.25 0.28

We can calculate the mean with the following formula:

$E(X) = \sum_{i=1}^n X_i P(X_i) = 3*0.07 +4*0.4 +5*0.25 +6*0.28= 4.74$

In order to find the variance we need to calculate first the second moment given by:

$E(X^2) = \sum_{i=1}^n X^2_i P(X_i) = 3^2*0.07 +4^2*0.4 +5^2*0.25 +6^2*0.28= 23.36$

And the variance is given by:

$Var(X) = E(X^2) +[E(X)]^2 = 23.36 -[4.74]^2 = 0.8924$

And the deviation would be:

$Sd(X) =\sqrt{0.8924} =0.9447$

3 0

3 years ago

Simplify. (-5.12) - (-4.7) (7.021)

aksik [14]

First, you should do the product first:
(-4.7)* (7.021)= -32.9987

Then, let's do the subtraction:
(-5.12)- (-32.9987)
= (-5.12)+ 32.9987
= 27.8787

Final answer: 27.8787

Hope this would help~

7 0

3 years ago

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Drag each number to the correct location on the equations. Each number can be used more than once, but not all numbers will be u

7nadin3 [17]

The system of equations to find the cost of one adult ticket, a, and the cost of one child ticket, c are Roy's; 6a+2c=66 Elisa's 5a+4c=62.

<h3>What is a system of equations?</h3>

A system of equations is two or more equations that can be solved to get a unique solution. the power of the equation must be in one degree.

Let's consider adults tickets be a and child tickets be c

Roy's purchase

6a+2c=66------1

Elisa's purchase

5a+4c=62-------2

Hence, the system of equations

6a+2c=66------1

5a+4c=62-------2

solving simultaneously

6a+2c=66

5a+4c=62

Also,

12a+4c=132

-5a+4c=62

7a=70

a=$10

put a=70 in 1

6(10)+2c=66

60+2c=66

2c=66-60

2c=6

c=$3

Learn more about equations here;

brainly.com/question/10413253

#SPJ1

4 0

1 year ago