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Minchanka [31]
3 years ago
15

Write and equation for the trend line shown

Mathematics
1 answer:
Zepler [3.9K]3 years ago
7 0

Answer:

y = -\frac{10}{3}<em>x</em> + 70

or

y = 70 -\frac{10}{3}x

(They're both the same equation, whichever one you prefer you can use!)

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I need help I have like 3 more questions
KatRina [158]
To find the answer, you have to set up a rate! The easiest way to do this would be to have:

160 beats / 60 seconds
25 beats / 10 seconds

From here, you can just look at the numbers. You want to get the two to have the same divisor, so you should multiply (25 beats / 10 seconds) by 6, because 6 * 10 = 60 seconds!

In conclusion, her heart rate when playing basketball is 160bpm, while her heart rate when jogging is 150bpm.

This means that her heart rate goes up more when she is playing basketball than when she is jogging!
8 0
3 years ago
Read 2 more answers
Geometry question below
Alex

Answer:

MN║SU

OM║TU

ST = 2ON

Step-by-step explanation:

3 0
3 years ago
Find the equation of a line parallel to 2x-3y+6=0, with the same y-intercept as y=7x-1
shepuryov [24]
The answer is y=2/3x -1
5 0
3 years ago
Ima cry brainliest giving it out
KatRina [158]

Answer:

23.1%

Step-by-step explanation:

11/48=0.23125

Round up for percent.

0.231x100=23.1

23.1%

3 0
3 years ago
Ray
monitta

We are given that:

m∠AOB = m∠AOC + m∠COB

We are also given that:

m∠AOC = m∠COB + 15

m∠AOB = 155

Therefore:

155 = m∠COB + 15 + m∠COB

2 m∠COB = 140

m∠COB = 70°

and,

m∠AOC = m∠COB + 15 = 85°

 

Answers:

m∠COB = 70°

m∠AOC = 85<span>°</span>

6 0
3 years ago
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