X²/9 + y²/16 = 1
The general for mula of an ellipse is:
(x-h)²/a² + (y-k)²/b² = 1. Since h = k = 0, this ellipse
x²/9 + y²/16 = 1
passes by the center O. (Note that a = 3 and b = 4)
Moreover sin b>a so the majore axis is (on the y-axis) and a the minor axis (on the x-axis) [Its shape is as a vertical egg].
On a system of perpendicular axis that intercept in O., take on the x-axis 2 points A & B with respective coordinate A(3.0) and B(-3,0)
On the y-axis your report A'(0,+4) and B'(0,-4). So you have the vertex of the ellipse, then it's easy to draw it
Answer:
Domain: {x | x is all real numbers} Range: {y | y ≥ 6}
Step-by-step explanation:
Domain is the set of all x values. No operations restrict the domain in this case. The domain is all real numbers.
Range is the set of all y values. Absolute value has a v shape starting at 0. Adding 6 raises this vertex to 6. The range is therefore all numbers greater than or equal to 6.
Step-by-step explanation:
option C
hope it helps
thank you
