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3 years ago

7

Write the ratio 8:20 in the simplest form

2 answers:

allsm [11]3 years ago

7 0

The ratio in simplest form is 2:5

Pavlova-9 [17]3 years ago

4 0

Ratios are fractions so to simplify 8/20 see what the numerator and denominator are both divisible by. That would be 4. Divide 8 by 4 and 20 by 4 to get 2/5 which is your simplified ratio of 8:20. So the answer is 2:5.

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Okay so I sort of get all of this, but how do I solve any of these? How does the equations work? Can someone please help me out

Andrej [43]

For 1 you have to. juat but the variable on one side side like for a)9x=5x+8 and minus 5x on both sides which equals 4x=8 then divide both sides by 4 to get x by itself which equals x=2

For 2 you have to distribute like a)2(x-3)=15 is 2x-6=15 because you distribute 2 with x-3

For 3 just plug in the value like since it said x=2 so 3x to 3(2) and just multiply

For 4 just move variable on one side lime for 1 but twice

For 5 distribute and move variables on one side to another but for B you have to combine like terms like 6z-z=5z

Hope this helps even though its alot

3 0

3 years ago

WHAT VALUE IS EQUIVALENT TO (7+3)^2 + (8-1) X 5 EQUAL

sdas [7]

Answer:

135

Step-by-step explanation:

(7+3)^2 + (8-1) * 5

Parentheses first

(10)^2 + (7) * 5

Exponents next

100 + 7*5

Multiply

100 + 35

Add

135

7 0

3 years ago

Use implicit differentiation to find an equation of the tangent line to the curve at the given point. x2/3 + y2/3 = 4 (−3 3 , 1)

vovikov84 [41]

Answer with Step-by-step explanation:

We are given that an equation of curve

$x^{\frac{2}{3}}+y^{\frac{2}{3}}=4$

We have to find the equation of tangent line to the given curve at point $(-3\sqrt3,1)$

By using implicit differentiation, differentiate w.r.t x

$\frac{2}{3}x^{-\frac{1}{3}}+\frac{2}{3}y^{-\frac{1}{3}}\frac{dy}{dx}=0$

Using formula : $\frac{dx^n}{dx}=nx^{n-1}$

$\frac{2}{3}y^{-\frac{1}{3}}\frac{dy}{dx}=-\frac{2}{3}x^{-\frac{1}{3}}$

$\frac{dy}{dx}=\frac{-\frac{2}{3}x^{-\frac{1}{3}}}{\frac{2}{3}y^{-\frac{1}{3}}}$

$\frac{dy}{dx}=-\frac{x^{-\frac{1}{3}}}{y^{-\frac{1}{3}}}$

Substitute the value x= $-3\sqrt3,y=1$

Then, we get

$\frac{dy}{dx}=-\frac{(-3\sqrt3)^{-\frac{1}{3}}}{1}$

$\frac{dy}{dx}=-(-3^{\frac{3}{2}})^{-\frac{1}{3}}=-\frac{1}{-(3)^{\frac{3}{2}\times \frac{1}{3}}}=\frac{1}{\sqrt3}$

Slope of tangent=m= $\frac{1}{\sqrt3}$

Equation of tangent line with slope m and passing through the point $(x_1,y_1)$ is given by

$y-y_1=m(x-x_1)$

Substitute the values then we get

The equation of tangent line is given by

$y-1=\frac{1}{\sqrt3}(x+3\sqrt3)$

$y-1=\frac{x}{\sqrt3}+3$

$y=\frac{x}{\sqrt3}+3+1$

$y=\frac{x}{\sqrt3}+4$

This is required equation of tangent line to the given curve at given point.

8 0

4 years ago

Consider the equation 1.5 x plus 4.5 y equals 18.

Otrada [13]

1.5x will be the very answer

6 0

3 years ago

Please help 15 points

Gwar [14]

Answer:

46/100

Step-by-step explanation:

The decimal reaches a point into the hundreths.

<em>kiniwih426</em>

5 0

3 years ago

Read 2 more answers