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kvasek [131]
2 years ago
15

How do I get to the answer of this question?

Mathematics
1 answer:
Elena L [17]2 years ago
3 0

Triangle Similarity

We will use the SAS theorem to prove that Triangle TSG and Triangle PHG are similar.

First, we need to define the SAS similarity theorem:

<em>The Side-Angle-Side (SAS) Theorem states if two sides of one triangle are proportional to two corresponding sides of another triangle, and their corresponding included angles are congruent, the two triangles are similar.</em>

To use this theorem, we need to prove:

* Two sides of the triangles are in the same proportion

* The included angle between them is congruent with the other corresponding angle.

In triangle TSG, the longest side has a length of 7.5 + 5 = 12.5 feet

In triangle PHG, the longest (and therefore corresponding) side has a length of 5 feet.

The ratio between them is 12.5 / 5 = 2.5

In triangle TSG, the horizontal length is 4.5 + 3 = 7.5 feet

In triangle PHG, the horizontal (and therefore corresponding) side has a length of 3 feet.

The ratio between them is 7.5 / 3 = 2.5

Since the ratio measured on both corresponding sides is the same, we have satisfied the first condition of the SAS theorem.

The included angle is G, and it's the same for both triangles.

The reflexive property guarantees both triangles have congruent corresponding angles:

Angle G is congruent with (itself) Angle G

Thus, we have met the conditions for the SAS similarity theorem and therefore proven Triangle TSG and Triangle PHG are similar.

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Select two statements that are true about the equation y+4=-8(x-2)
bezimeni [28]

Answer:

Step-by-step explanation:

y + 4 = -8(x - 2)

I dont know the statements that u have but maybe I can guess one...or two

slope = -8

points used were : (2,-4)

y + 4 = -8(x - 2)

y + 4 = -8x + 16

y = -8x + 16 - 4

y = -8x + 12 ............slope intercept form

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5 0
3 years ago
Read 2 more answers
MATH WORD PROBLEM
Sloan [31]

cost of one regular admission ticket = $ 10

cost of one senior citizen ticket = $ 5

<h3><u>Solution:</u></h3>

Let "r" be the cost of one regular admission ticket

Let "s" be the cost of one senior citizen ticket

Given that,

<em><u>On day 1 you sold 30 Regular Admission tickets and  20 Senior Citizen tickets for a total of $400</u></em>

So we can frame a equation as:

30 Regular Admission tickets x cost of one regular admission ticket + 20 Senior Citizen tickets x cost of one senior citizen ticket = $ 400

30 \times r + 20 \times s = 400

30r + 20s = 400 ----- eqn 1

<em><u>Day two you sell 40 Regular Admission tickets and only 10 Senior  Citizen tickets for a total of $450</u></em>

So we can frame a equation as:

40 Regular Admission tickets x cost of one regular admission ticket + 10 Senior Citizen tickets x cost of one senior citizen ticket = $ 450

40 \times r + 10 \times s = 450

40r + 10s = 450 ---- eqn 2

<em><u>Let us solve eqn 1 and eqn 2 to find values of "r" and "s"</u></em>

Multiply eqn 2 by 2

80r + 20s = 900 --- eqn 3

Subtract eqn 1 from eqn 3

80r + 20s = 900

30r + 20s = 400

(-) ---------------------

50r = 500

<h3>r = 10</h3>

Substitute r = 10 in eqn 1

30r + 20s = 400

30(10) + 20s = 400

300 + 20s = 400

20s = 100

<h3>s = 5</h3>

<em><u>Thus we have:</u></em>

cost of one regular admission ticket = $ 10

cost of one senior citizen ticket = $ 5

4 0
4 years ago
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