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Jlenok [28]
3 years ago
5

Select the correct answer from the drop-down menu. Consider the equations y = |x − 1| and y = 3x + 2. The approximate solution o

f this system of equations is
Mathematics
1 answer:
Scrat [10]3 years ago
5 0
<span>y = |x − 1|→y=x-1, if x-1>=0
                    y=-(x-1), if x-1<0

Then if x-1>=0→x>=1, y=x-1
         if x-1<0→x<1→y=-(x-1)=-x+1→y=-x+1

For x>=1
y=x-1
y=3x+2
Solving for x by equaliting's method:
y=y→3x+2=x-1→3x+2-x-2=x-1-x-2→2x=-3→2x/2=-3/2→
x=-3/2<1 No solution

For x<1
y=-x+1
y=3x+2
</span>Solving for x by equaliting's method:
y=y→3x+2=-x+1→3x+2+x-2=-x+1+x-2→4x=-1→4x/4=-1/4→
x=-1/4<1  Ok
<span>
y=-x+1
y=-(-1/4)+1
y=1/4+1
y=(1+4)/4
y=5/4

The approximate solution of this system of equations is
(x,y)=(-1/4,5/4)=(-0.25,1.25)
 </span>
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meriva

Answer:

67.38

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A game is played with a spinner on a circle, like the minute hand on a clock. The circle is marked evenly from 0 to 100, so, for
zheka24 [161]

Answer:

The probability is 1/2

Step-by-step explanation:

The time a person is given corresponds to a uniform distribution with values between 0 and 100. The mean of this distribution is 0+100/2 = 50 and the variance is (100-0)²/12 = 833.3.

When we take 100 players we are taking 100 independent samples from this same random variable. The mean sample, lets call it X, has equal mean but the variance is equal to the variance divided by the length of the sample, hence it is 833.3/100 = 8.333.

As a consecuence of the Central Limit Theorem, the mean sample (taken from independant identically distributed random variables) has distribution Normal with parameters μ = 50, σ= 8.333. We take the standarization of X, calling it W, whose distribution is Normal Standard, in other words

W = \frac{X - \mu}{\sigma} = \frac{X - 50}{8.333} \simeq N(0,1)

The values of the cummulative distribution of the Standard Normal distribution, lets denote it \phi , are tabulated and they can be found in the attached file, We want to know when X is above 50, we can solve that by using the standarization

P(X > 50) = P(\frac{X-50}{8.33} > \frac{50-50}{8.33}) = P(W > 0) = \phi(0) = 1/2

Download pdf
8 0
3 years ago
20PTS Question On Pic Thx
harina [27]

Answer:

  (a)  $3800

  (b)  (a) -- April to May

Step-by-step explanation:

<h3>(a)</h3>

The least amount is found at the lowest point on the graph. That point is in May. It is on the line between 3700 and 3900, so the amount is $3800.

The least donation amount is a month is $3800.

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<h3>(b)</h3>

The greatest month-to-month decrease is found where the line on the graph has the steepest negative slope. There are two segments with negative slope:

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The decrease from April to May is by far the largest of these two decreases.

The greatest decrease occurred April to May.

6 0
2 years ago
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I need help with these this is due today
Oduvanchick [21]

Answer:

Yah no way man your gonna fail

Step-by-step explanation:

5 0
2 years ago
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(3,15) is the solution for what equation
juin [17]
<span>Hello there, i think the answer is 15=3*5
(Please leave a thanks if this IS the right answer! Thanks ;)
What times 3 = 15?
x*3=15
X=5</span>
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3 years ago
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