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3 years ago

Riaz wants to spend no more than $1,250 on his trip. The airfare is $439. Write and solve an inequality to find the maximum amou

nt he can spend on the rest of his trip.

Mathematics

1 answer:

Ilya [14]3 years ago

4 0

$Answer: \\ Let \: x \: be \: the \: amount \: of \: money \: he \: can \: spend \\ We \: have \: an \: inequality:x +439 \leqslant 1250 \\ \Leftrightarrow x \leqslant 811 \\ So \: the \: maximum \: amount \: he \: can \: spend \: is \: \$ 811$

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$\qquad\qquad\huge\underline{{\sf Answer}}♨$

Let's solve ~

Assume width of rectangle be " x ", length = 3×width + 8 = 3x + 8 ~

Now, Perimeter of rectangle is :

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$\qquad \sf \dashrightarrow \:2(3x + 8 + x) = 56$

$\qquad \sf \dashrightarrow \:2(4x + 8) = 56$

$\qquad \sf \dashrightarrow \:4x + 8 = 56 \div 2$

$\qquad \sf \dashrightarrow \:4x + 8 = 28$

$\qquad \sf \dashrightarrow \:4x = 28 - 8$

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$\qquad \sf \dashrightarrow \:x =5 \: cm$

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$\qquad \sf \dashrightarrow \:l = 15+ 8$

$\qquad \sf \dashrightarrow \:l =23 \:cm$

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