Answer: 1/3
Step-by-step explanation:
From the question, we are informed that Pranav ate pizza for dinner on Monday night and had 2/3 of the pizza left over. We are further told that on Tuesday night, he ate 1/2 of what was left.
The amount of pizza that Pranav ate on Tuesday will be:
= 1/2 × 2/3
= 1/3
She ate 1/3 on Tuesday
Collection or percolation
Answer: 4/15
Step-by-step explanation:
1/3+2/5 change it to 5/15+6/15=11/15 4/15 left of the lawn
YESn Okau bye him yea oasis
Answer:
A=-3/2
B=3
c=3/2
a=-2
Step-by-step explanation:
Knowing that for
,
when t<0 and using the definition of charge

The first term corresponds to q(0), the charge accumulated before t=0, in this case it luckily gives zero so we don't have to worry about it.
Let's proceed and integrate
then when t>0
![i(t)=3\int_0^t \left[ \int_0^tdt'-\inte_0^t e^{-2t'}dt' \right]dt'=3\left[ t+\frac{1}{2}\left( e^{-2t}-1 \right) \right]=3t+\frac{3}{2}e^{-2t}-\frac{3}{2}\,\, C](https://tex.z-dn.net/?f=i%28t%29%3D3%5Cint_0%5Et%20%5Cleft%5B%20%5Cint_0%5Etdt%27-%5Cinte_0%5Et%20e%5E%7B-2t%27%7Ddt%27%20%5Cright%5Ddt%27%3D3%5Cleft%5B%20t%2B%5Cfrac%7B1%7D%7B2%7D%5Cleft%28%20e%5E%7B-2t%7D-1%20%5Cright%29%20%5Cright%5D%3D3t%2B%5Cfrac%7B3%7D%7B2%7De%5E%7B-2t%7D-%5Cfrac%7B3%7D%7B2%7D%5C%2C%5C%2C%20C)
It is clear that:
A=-3/2
B=3
c=3/2
a=-2