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2 years ago

Which expressions represent the distance between the two points?

1 answer:

8 0

On the number line, the distance between negative 11 and positive 7 is <em>18 units</em>.

Choice A: The absolute value of (-11 - 7) = absolute value of (-18) = 18.

Choice C: The absolute value of [ 7 - (-11) ] = absolute value of (7+11) = 18.

'A' and 'C' are both the same number, and it's the correct answer to the question.

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How can you check your answer in unit rates?

muminat

Answer:

<h3>⭐In a unit rate, the denominator is always 1. So, to find unit rate, divide the denominator with the numerator in a way that the denominator becomes 1. For example, if 50km is covered in 5.5 hours, the unit rate will be 50km/5.5 hours = 9.09 km/hour.</h3>

Step-by-step explanation:

<h2>⛄I hope it's helpful for you ⛄</h2>

6 0

2 years ago

Read 2 more answers

<1 and <2 form a linear pair. The measure of <2 is six more than twice the measure of <1. Find the measure of <2

MrMuchimi

Answer:

122 Degrees

Step-by-step explanation:

Since we are given that angle 1 and 2 make a linear pair:

angle 1 + angle 2 = 180 degrees ----------------------------(1)

We have also been told that angle 2 is 6 more than twice the measure of angle 1

Which means: angle 2 = (2*angle1) + 6 -------------------(2)

From putting the value of angle 2 in (1) from (2)

<em>angle 1 + 2*angle 1 + 6 = 180</em>

<em>3*angle 1 = 174</em>

angle 1 = 58 degrees -----------------------(3)

From (1) and (3):

<em>angle 2 + 58 = 180</em>

angle 2 = 122 degrees

Therefore, the measure of angle 2 is 122 degrees

7 0

3 years ago

In 2002, there were 972 students enrolled at Oakview High School. Since then, the number of students has increased by 1.5% each

Rudiy27

Answer:

$N(t) = 972(1.015)^{t}$

Growth function.

The number of students enrolled in 2014 is 1162.

Step-by-step explanation:

The number of students in the school in t years after 2002 can be modeled by the following function:

$N(t) = N(0)(1+r)^{t}$

In which N(0) is the number of students in 2002 and r is the rate of change.

If 1+r>1, the function is a growth function.

If 1-r<1, the function is a decay function.

In 2002, there were 972 students enrolled at Oakview High School.

This means that $N(0) = 972$

Since then, the number of students has increased by 1.5% each year.

Increase, so r is positive. This means that $r = 0.015$

Then

$N(t) = N(0)(1+r)^{t}$

$N(t) = 972(1+0.015)^{t}$

$N(t) = 972(1.015)^{t}$

Growth function.

Find the number of students enrolled in 2014.

2014 is 2014-2002 = 12 years after 2002, so this is N(12).

$N(t) = 972(1.015)^{t}$

$N(12) = 972(1.015)^{12}$

$N(12) = 1162$

The number of students enrolled in 2014 is 1162.

7 0

2 years ago

Which of the following has a slope of -3 and a y-intercept of -4?

tresset_1 [31]

The correct answer is C

6 0

3 years ago

name a transformation that does not always produce an image that would be congruent to the original figure

Kay [80]

A dilation is the best answer. A dilation shrinks or expands the shape on a plane. But now, that shape is the same shape, but a different size.
Congratulations! You have discovered simillar figures. They are the same shape, but different sizes, so they are not congruent.
Hope this helps

3 0

3 years ago