Answer:
4cotα=tanα
4(1/tanα)=tanα
(4/tanα)=tanα
cross multiply
=> 4=tan²α
√4=√tan²α
±2=tanα
α=arc( tan) |2|
α=63.4° ( in first quadrant)
and
α=180+63.4=243.4 in the third quadrant
since we also found a negative answer( i.e –2) then α also lies in quadrants where it gives a negative value(i.e second and fourth quadrants)
α=180–63.4=116.6° in the second quadrant
α=360–63.4=296.6 in the fourth quadrant
therefore theta( in my case, alpha) lies in all four quadrants and is equal to:
α=63.4°,243.4°,116.6°and 296.6°
We have been given that the scale on a trail map is 0.5 cm : 1 km. The straight distance between 2 huts on the trail is 16.9 cm. We are asked to find the actual distance between 2 huts.
We will use proportions to solve our given problem.
Therefore, the actual distance between both huts is 33.8 km.
Irrational will be the answer
The values of n that either player has a winning strategy is when the number of points are odd such as 3:-
<h3>How to depict the strategy?</h3>
The game is begun by A and then its chance of B to play the game alternatively, then all the possible moves are 1,2; 2,3; 1,3 in which all possible pairs are selected.
If the game end on an even number of moves then the game is won by A. For B to win, these points should be connected at the very end of the game.
Similarly, for even number of moves B wins the game when number of points is odd.
If the number of points is even the opposite of this happens that is, for even moves B wins and for odd number of moves A wins.
Learn more about strategy on:
brainly.com/question/24499246
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